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Zielflug [23.3K]
3 years ago
7

Can a object that measures 1.8 metres by 1.2 metres fit in a gap that measure 1 metre by 0.75 metres

Mathematics
1 answer:
Paha777 [63]3 years ago
4 0
No it cannot because 1.8 and 1.2 are both larger than 0.75 so there is no physical way for it to fit
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The Fairy Tell Spectacular is coming to town. Admission to the fair cost $32.50 and each ride cost $0.08. You have $50 to spend
Vikki [24]

0.08x + 32.50 = 50
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3 0
3 years ago
WHAT IS THE VALUE OF 2 IN 80,250 PLEASE HELP ME
labwork [276]

Hey there!

80,250 \\ \\ \\ \\ 8 = 80,000 = (Ten) Thousand \\  0 = 0 = Thousands \\ \\  2= 200 = Hundreds \\ 50 = 50 = Tens \\ 0 = 0 = Ones

So, therefore... the value 2 in this number would be Hundreds

Answer: Hundreds

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0
3 years ago
The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:
blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

  =\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182

Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

      =\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899

Thus, the standard deviation of the age distribution is 6.2899 years.

7 0
3 years ago
What are statements that are true for any number
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It can be less than, more than or equal to zero
6 0
3 years ago
What is the domain and range for y=-x^2-8x-16
mr_godi [17]
It’s in the picture , i hope this helped you

4 0
3 years ago
Read 2 more answers
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