Answer:
3 cups
Step-by-step explanation:
We can use a proportion to find how many cups of chocolate chips she needs for 30 servings. Assuming c = cups of chocolate chips and b = batches
![\frac{c}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Bc%7D%7Bb%7D)
![\frac{1}{10} = \frac{c}{30}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%20%3D%20%5Cfrac%7Bc%7D%7B30%7D)
We can now multiply the diagonal values that don't include the missing variable (30 and 1) and then divide it by the value that is diagonal to the variable (10)
![30 \cdot 1 = 30\\30 \div 10 = 3](https://tex.z-dn.net/?f=30%20%5Ccdot%201%20%3D%2030%5C%5C30%20%5Cdiv%2010%20%3D%203)
Therefore, she needs 3 cups of chocolate chips to make 30 servings.
Answer:
1000000000000000000000
Step-by-step explanation:
just multiply it ;-; or add 2 zeros in 1,0000000000000000000
To determine if it is a function or not, you can not have a vertical line drawn down the graph touch 2 of the graphed points. That means that you can not have 2 points with the same x value and different Y value. The first set of points satisfies this and is your answer. Hope that helps.
Answer:
its the the second one not the first one
Answer:
3/2 < x < 2
Step-by-step explanation:
We assume the problem is ...
[tek]\dfrac{1}{x-2}<-2[/tex]
This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...
1 > -2(x -2)
1 > -2x +4
2x > 3 . . . . . . add 2x-1
x > 3/2
From above, we also have x < 2, so the solution set is ...
3/2 < x < 2