Answer with Step-by-step explanation:
The height of the ball from the ground as a function of time is given by

The height of the ball at any instant of time can be found by putting the value of time 't' in the above relation as
Part a)
Height of ball after 2 seconds it is released is

Part b)
Height of ball after 4 seconds it is released is

(5,24)
- The two areas are the same.
- To find the area, we multiply the side lengths. Y=area
Rectangle 1: side lengths 4 and (x+1)
y=4(x+1)= 4x+4
Rectangle 2: side lengths 3 and (2x-2)
y=3(2x-2)= 6x-6
- Since the two areas are same, we can conclude that
4x+4=6x-6
-2x=-10, x=5
- Since x is 5, we can plug it into the equations to find y.
Option 1 with rectangle 1: y=4(5)+4, y=24
Option 2 with rectangle 2: y=6(5)-5, y=24
I graphed the linear equation on desmos.
Answer:
15.87%
Step-by-step explanation:
Notice that the mean of 0.35 inches with a standard deviation of 0.01 gives you when you add (to the right of the distribution), exactly 0.36. Since you want to find the probability (or percentage) of the bolts that have diameter LARGER than 0.36 in, that means you want to estimate the area under the Normal distribution curve from 0.36 to the right). See attached image.
We can use the tables of Z distribution for that, or the standard normal tables:
P(x>0.36) = P(z>(0.36-0.35)/0.01) = P(Z>1) = 0.1587 = 15.87%