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2 years ago

2 divided by 1 and 6/7

1 answer:

8 0

This problem, as written, requires a bit of guessing regarding your intentions. My interpretation is that you want to do this division:

----------

1 6/7

If that's correct, here's what to do: rewrite 1 6/7 as 13/7 (an improper fraction).

Then divide:

-------- This is equivalent to the multiplication (2/1)(7/13) = 14/13 (answer)

13/7

You might be interested in

Y is inversely proportional to x.

Inessa [10]

Answer:

1. $xy = 63$

2. $y = 3$

Step-by-step explanation:

Given

Variation: inverse Proportion

y = 7, x = 9

Required

- Write an equation connecting y and x

- Find y when x = 21

Given that thee variation is inversely proportional;

This implies that

$y\ \alpha\ \frac{1}{x}$

Convert variation to equation

$y\ = \frac{k}{x}$ ----------- Equation 1

Where k is the constant of variation

Substitute 7 for y and 9 for x in equation 1

$7 = \frac{k}{9}$

Multiply both sides by 9

$9 * 7 = 9 * \frac{k}{9}$

$63 = k$

Substitute 63 for k in equation 1

$y = \frac{63}{x}$

Multiply both sides by x

$x * y = \frac{63}{x} * x$

$xy = 63$

Hence, the equation connecting x and y is $xy = 63$

Solving for when x = 21

Substitute 21 for x in the above equation

$21 * y = 63$

Divide both sides by 21

$\frac{21 * y}{21} = \frac{63}{21}$

$y = 3$

4 0

3 years ago

Tony made $396 for 18 hours of work at the same rate how many hours would he have to work to make $198

tresset_1 [31]

Answer:

9 hours.

Step-by-step explanation:

So, first, you have to determine what he makes per hour to make this as easy as possible. You need to first do 396 divided by 18, which gives you 22. He makes 22$ an hour. Next, now that you know what he makes, you can do 198 divided by 22, and that'll show how long he has to work to make that amount of money.

Hope this helped. Please mark this brainliest if you think this helped. Let me know if you need anymore help and I am more than happy.

7 0

3 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers: