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3 years ago

10. What are the missing side lengths in TSU? Explain. Keep your a answer in

Mathematics

1 answer:

Gemiola [76]3 years ago

5 0

Use sah coh toa. Sin cos and tan

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Pleaseee helpppp asaappppb:((((

VikaD [51]

Answer:

5.) •Response

6.) • Experimental unit

5 0

3 years ago

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan

Crank

Answer:

Step-by-step explanation:

We are given coordinates of the line passed through (–5, –1) and (10, –7) .

Applying slope formula,

$Slope=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-5,\:-1\right),\:\left(x_2,\:y_2\right)=\left(10,\:-7\right)$

Therefore,

$m=\frac{-7-\left(-1\right)}{10-\left(-5\right)}$

$m=-\frac{2}{5}$

Therefore, slope is $m=-\frac{2}{5}$ .

Applying point-slope form $y-y_1=m(x-x_1),$ we get

$y+7 = -\frac{2}{5}(x-10)$

$y+7=-\frac{2}{5}(x-10)$

On multiplying both sides by 5, we get

$5(y+7)=5\times-\frac{2}{5}(x+1)$

5y+35=-2(x-10)

5y+35=-2x+20

Adding 2x on both sides, we get

5y+25+2x=-2x+20+2x

2x+5y+35=20

Subtracting 35 from both sides, we get

2x+5y+35-35=20-35

2x+5y=-15.

Therefore, required equation is :

6 0

2 years ago

A movie rental store charges a $6 membership fee plus $2.50 for each movie rented. What are the slope and y-intercept that repre

Olegator [25]

There searched up please be correct

8 0

2 years ago

Read 2 more answers

33pt =__ qt __qt pliz. hurry

Valentin [98]

<span>16.5
1 pint(US) = 0.5 quarts (US)</span>

5 0

2 years ago

A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib

fenix001 [56]

Answer: 0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = $\mu=50\times190=9500\text{ pounds}$

Standard deviation of 50 people $=\sigma=40\sqrt{50}=40(7.07106781187)=282.84$

Then , the probability its maximum safe load will be exceeded =

$P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855$

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0

3 years ago