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Aleks04 [339]
3 years ago
12

10. What are the missing side lengths in TSU? Explain. Keep your a answer in

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0
Use sah coh toa. Sin cos and tan
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Ace please help plsss​
Ivanshal [37]

Answer:

B

Step-by-step explanation:

I Think I Got It Right But This Is From A LONG time ago

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2 years ago
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Which systems are most responsible for removing unwanted substances from the body
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Respiratory and urinary
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3 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?
adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)

\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t  \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}

$$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$$

3 0
2 years ago
Find the solution to the equation below.
Andreyy89

Answer:

B and D

Step-by-step explanation:

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}. Here a=20, b=-26, and c=8.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{26+/-\sqrt{26^2-4(20)(8)} }{2(20)}=\frac{26+/-\sqrt{676-640} }{40)}

\frac{26+/-\sqrt{36} }{40}=\frac{26+/-6 }{40}

This means the solutions are 26 - 6/ 40 and 26 + 6/ 40.

It simplifies to 1/2 and 4/5.

3 0
3 years ago
Use the x-intercept method to find all real solutions of the equation. -9x^3-72x^2+36=3x^3+x^2-3x+8
larisa86 [58]

-9x^3-72x^2+36=3x^3+x^2-3x+8                     Add 9x^3 to both sides.

-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8       Add 72x^2 to both sides

36 = 12x^3 +   73x^2 - 3x + 8                           Subtract 36 from both sides.

0 = 12x^3 + 73x^2 - 3x - 28      

It does factor, but it is not very nice.

(x + 6.06)(x - 6.09)(x + 0.632)

If there is any kind of error please report it in a note below.

6 0
3 years ago
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