The area of the tennis court is computed by multiplying the dimensions given,
A = 120' x 80'
A = 9600 ift
Then, we convert the area in ft² to acres,
A = (9600 in²)(2.3 x 10^-5/ 1 in²)
A = 0.24 acre
The portion of land remaining is,
A of remaining = 0.25 acre - 0.24 acre
= 0.1 acre
The remaining portion is for Andre's studies.
This, 0.1 ft² is equal to the 4% of the given area of the court.
The answer is 4,162 for 564+3,598
8 ÷ 11 = 0.72727272...
Therefore, decimal '72' is repeating
A sector is a <u>part</u> of a <u>circle</u> that is formed by two<em> radii,</em> and an <em>arc</em>. So that the length of the <em>safety railing</em> required is 31.4 feet.
A sector is a <em>part </em>of a <u>circle</u> that is formed by two <u>radii</u>, and an <u>arc</u>, thus forming a <em>central</em> angle.
Thus the required <em>length</em> of safety railing can be considered as the <u>arc</u> of the<em> sector. </em>
So that;
<u>length</u> of an <u>arc</u> = (θ /
) * 2
r
where θ is the <u>measure</u> of the <em>central angle</em> of the sector, and r is the <u>radius</u> of the sector.
From the given question, θ = 45°, and r = 40 feet.
So that,
<u>length</u> of the<em> safety railing </em>= (45° /
) * 2 * 3.14 * 40
= 0.125 * 2* 3.14* 40
<u>length</u> of <em>safety railing</em> = 31.4
Therefore, the <u>length</u> of the <em>safety railing</em> required is 31.4 feet.
For more clarifications on the length of an arc, visit: brainly.com/question/2005046
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Answer: 200x^2y+640x^2+1010xy+3232x-2380y-7616
Step-by-step explanation:
((8x−14)(5y+16))(5x+34)
((8x−14)(5y+16))(5x)+((8x−14)(5y+16))(34)
200x2y+640x2−350xy−1120x+1360xy+4352x−2380y−7616
200x2y+640x2+1010xy+3232x−2380y−7616