Answer:
12
Step-by-step explanation:
1/3 of 12 = 4
1/4 of 12 = 3
4 is 1 more than 3.
The number is 12.
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If this does not immediately come to mind, you can solve for the number, x:
x/3 -x/4 = 1 . . . . the difference between 1/3 of x and 1/4 of x is 1
x/12 = 1 . . . . . . . collect terms: (1/3 -1/4 = 4/12 -3/12 = 1/12)
x = 12 . . . . . . . . multiply by 12
Answer:
a) False
b) False
c) True
d) False
e) False
Step-by-step explanation:
a. A single vector by itself is linearly dependent. False
If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.
b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False
A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.
c. The columns of an invertible n × n matrix form a basis for Rⁿ. True
If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.
d. In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False
Row operations can not affect linear dependence among the columns of a matrix.
e. A basis is a spanning set that is as large as possible. False
A basis is not a large spanning set. A basis is the smallest spanning set.
Answer:
Step-by-step explanation:
We have that:
When we substitute n=1, we get:
When we substitute n=2 we get:
When we substitute n=3, we get:
When we substitute n=n+1, we get:
Now
We expand and simplify to obtain:
Answer:
Jada's hamster walked a total of 6.75 feet.
Step-by-step explanation:
If this was not the answer you were looking for just let me know and i will help as much as i can.
U can either look at ur graph...and where the line crosses the x axis is ur x intercept...which is (-3,0)
OR
take ur equation and sub in 0 for y, and solve for x, ur x intercept.
2x - y = -6
2x - 0 = -6
2x = -6
x = -6/2
x = -3.....so ur x intercept is (-3,0)
