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cluponka [151]
4 years ago
15

10 POINTS!!! FULL ANSWER WITH FULL STEP BY STEP SOLUTION PLEASE

Mathematics
1 answer:
lora16 [44]4 years ago
5 0
Define z = ln(x). Then
  y = z^z
  y' = z^z * (z')*(1 +ln(z))
Since
  z' = 1/x
You have
  y' = ln(x)^ln(x) * (1/x) * (1 +ln(ln(x))

Evaluated at x=e, this becomes
  y'(e) = 1^1 * (1/e) * (1 +ln(1))
  y'(e) = 1/e
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