3 years ago

10 POINTS!!! FULL ANSWER WITH FULL STEP BY STEP SOLUTION PLEASE

1 answer:

5 0

Define z = ln(x). Then
y = z^z
y' = z^z * (z')*(1 +ln(z))
Since
z' = 1/x
You have
y' = ln(x)^ln(x) * (1/x) * (1 +ln(ln(x))

Evaluated at x=e, this becomes
y'(e) = 1^1 * (1/e) * (1 +ln(1))
y'(e) = 1/e

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The ratio of money in Terry's bank account to Faye's bank account was 3:5.

inn [45]

Answer:

<em>Terry had £780 initially and Faye had £1300</em>

Step-by-step explanation:

<u>System of Equations</u>

We'll call the following variables:

x = Terry's balance in his bank account

y = Faye's balance in her bank account

The initial relation between them is:

$\frac{x}{y}=\frac{3}{5}$

Cross-multiplying:

5x = 3y [1]

If Terry put £220 in his account he had x+220 and if Faye withdrew £300 from her account, she had y-300. Both quantities are equal, thus

x + 220 = y - 300

Subtracting 220:

x = y - 520 [2]

Substituting in [1]

5(y - 520) = 3y

Multiplying:

5y - 2600 = 3y

Adding 2600 and subtracting 3y:

2y = 2600

Dividing by 2:

y = 1300

From [2]:

x = 1300 - 520

x = 780

Terry had £780 initially and Faye had £1300

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2 years ago