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3 years ago

ABCD is a square. If m

Mathematics

1 answer:

AlekseyPX3 years ago

5 0

Answer:

????

Step-by-step explanation:

need more Info to answer correctly

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20% of 145 Please show work!!!! I need an answer ASAP!!!!

IRISSAK [1]

Answer:

20/100 × 145

2/10 × 145

290 ÷ 10 = 29

Thus, 20% of 145 is 29

5 0

3 years ago

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Convert (CAB) 16 to decimal need help asap

Mrrafil [7]

Remark

So CAB is a base 16 number? I hope that's correct. I'll treat it that way. If I am incorrect, please leave a note and I'll modify my answer accordingly.

Expand

A = 10 in decimal

B = 11 in decimal

C = 12 in decimal

B is the "units" value in decimal it is 11

A is the "tens" value or 12 place and in decimal you would get 12 * 10 = 120

C is the "hundreds" value or 12^2 place and in decimal you would get 144*12 =1728

Now you need to all all three results together. 11 + 120 + 1728 = 1850

Answer

(CAB)_16 = 1850 in decimal

6 0

3 years ago

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Solve for f(-3) f(x)=5-x f(-3)= ? pls helpppp

RoseWind [281]

F(-3) = 8

Plug -3 into x and just solve it.

5 0

3 years ago

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

P(0) = 0 and P(50) = 1,500,000

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The integrating factor is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

3 years ago

How do you write -4 1/5 as an improper fraction

jekas [21]

-21/5

Multiply 4 and 5, add 1

4 0

3 years ago

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