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3 years ago

Um can someone help me find x

Mathematics

1 answer:

Marysya12 [62]3 years ago

5 0

8x???? I could be wrong

Explained

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What’s the value of x? :/

kolbaska11 [484]

Answer:

$x = 27$

Step-by-step explanation:

According to congruent chords and arcs theorem, if $\overline{XY} \cong \overline{ZY}$ then $\arc{XY} \cong \arc{ZY}$ .

This means that $\arc{XY} = \arc{ZY} = (6x - 20) degrees$

Thus:

$\arc{XY} + \arc{ZY} + \arc{ZX} = 360$ (full circle = 360°)

$\arc{XY} = (6x - 20)$

$\arc{ZY} = (6x - 20)$

$\arc{ZX} = 76$

Plug in the values into the equation

$(6x - 20) + (6x - 20) + 76 = 360$

$6x - 20 + 6x - 20 + 76 = 360$

Add like terms

$12x + 36 = 360$

Subtract 36 on both sides

$12x = 360 - 36$

$12x = 324$

Divide both sides by 12

$x = 27$

8 0

3 years ago

Janelle wants to learn to play the piano. Her friends recommended three different music schools. Make Music charges $525 for 10

gulaghasi [49]

Music World give the best deal

5 0

2 years ago

Identify the "inside function" u = f(x) and the "outside function" y = g(u). Then find dy/dx using the Chain Rule.

skad [1K]

DfLet $f(x)=\sec x$ and $g(x)=\sqrt x$ . Then

$y=\sec\sqrt x=\sec(g(x))=f(g(x))=f\circ g(x)$

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

where $u=g(x)=\sqrt x$ , so that $y=f(g(x))=f(u)=\sec u$ . We have

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac1{2\sqrt x}$
$\dfrac{\mathrm d\sec u}{\mathrm du}=\sec u\tan u$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\sec u\tan u\dfrac{\mathrm dy}{\mathrm du}=\dfrac{\sec\sqrt x\,\tan\sqrt x}{2\sqrt x}$

5 0

3 years ago

A-shifted 4 units right and 3 units up

mart [117]

The answer should be B- shifted 3 units right and 2 units up. Sorry if it’s wrong!!! Good luck! :)

3 0

3 years ago

NEED ASAP!!

vivado [14]

Answer:

C and E

Step-by-step explanation:

A "constant function" has the same y-value for every x-value. Tables C and E match that description.

3 0

3 years ago