Question

Can someone please help? Only answer the question correctly, please! Question is down below.

Answer 1

Answer:

${6y}^{2}$

Step-by-step explanation:

Given,

$\frac{1}{ {6y}^{ - 2} }$

Since,

${x}^{ab} = {( {x}^{a} )}^{b}$

Hence,

$= \frac{1}{ {( {6y}^{2} )}^{ - 1} }$

Since,

$\frac{1}{ {x}^{ - 1} } = x$

Hence,

$= {6y}^{2} (ans)$