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Alenkinab [10]
4 years ago
7

Which angles are congruent to each other?

Mathematics
1 answer:
Nikolay [14]4 years ago
6 0

Answer:

The angles that are congruent due to being vertical angles are:

m∠2 and m∠4

m∠1 and m∠3

m∠8 and m∠6

m∠5 and m∠7

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Solve the inequality and show on a number line<br><br> (picture included below)
aksik [14]

Step-by-step explanation:

I cant show a number line so i'll do my best to explain how its graphed.

15) x - 1 < 15

add 1 to both sides:

x < 16

Because it is less than, rather than less than or equal to, it's graphed with an open circle (not filled in) on 16, and everything less than 16 highlighted

---------------------------------------------------------

16) 2(y + 1) - 2 ≥ 12

distribute the 2:

2y + 2 - 2 ≥ 12

combine like terms

2y ≥ 12

isolate y:

y ≥ 6

This one is greater than or equal to, so it's graphed with a closed circle (filled in) and everything above 6 highlighted

6 0
4 years ago
Read 2 more answers
Peter the optician sees 16 patients one Tuesday.4 are neither short nor long sighted,the total number of short sighted patients
My name is Ann [436]

The number of short-sighted patients is 7

The number of long-sighted patients is 5

The number of patients requiring a varifocal lens is 4

Step-by-step explanation:

Stepwise solution-

Throughout the question, only 3 types of patients are mentioned. Hence, it would be safe to assume that he saw/sees these 3 types of patients on Tuesday.

As per the given details-

4 are neither short-sighted patients nor long-sighted patients. Then it means no of varifocal lens patients is 4.

Hence remaining total patients=16-4=12

As given, no of short-sighted patients is 2 more than the number of long-sighted patients.

Let us assume the number of long-sighted patients as “x”

Thus, the number of short-sighted patients would be “x+2”

x+(x+2)=12   (total remaining patients)

2x=10

x=5

Hence, No. of long-sighted outpatients = 5

            No. of short-sighted outpatients =7

5 0
4 years ago
Need some help please with this math problem.Thanks.
ki77a [65]
Honestly I don’t even know what this question is trying to ask
3 0
4 years ago
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2,
Mandarinka [93]

Answer:

C is the equation that is perpendicular and goes through the given point.

Step-by-step explanation:

In order to find this, we first need to find an equation with the appropriate slope. Perpendicular lines have opposite and reciprocal slopes. Since the slope of the original line is 1, we need a line with -1 slope. C and D are the only such answers that have this slope.

Next we look for it to fit into the following point slope equation.

y - y1 =m(x - x1)

We use the point (2, 5) as (x1, y1). So we can plug those in the spots that we see above as well as the slope at m.

y - y1 =m(x - x1)

y - 5 = -(x - 2)

7 0
4 years ago
What is the slope of this line?<br><br> A. −34<br> B. −3<br> C. 34<br> D. 4
ICE Princess25 [194]

Answer:

-3/4

Step-by-step explanation:

It should be -3/4 . The line doesn't have an upward slope going to the right so that means it's negative . that already eliminates C and D . So -3/4 would be right

4 0
3 years ago
Read 2 more answers
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