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spin [16.1K]
3 years ago
7

Help Dana find the sum 346 421 152

Mathematics
1 answer:
lara [203]3 years ago
7 0

Dana wants to find the sum

  3 4 6

  4 2 1

+1 5 2

________

We will not regroup this ones place because the sum of the digits in the ones place is not up to. It's just 6+1+2 = 9.

Therefore, 13a) No.

There is no regrouped tens to add, so we would not able to regroup the ones place.

Therefore, 13b) No.

We regroup the tens place because the sum of the digits in the ones place is upto to 10.

And 13c) Yes.

We add the regrouped hundred as we regrouped the ones place.

Therefore,

13 D) Yes.






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3 0
3 years ago
1. What is the solution of n² – 49 = 0? (1 point)
maks197457 [2]

Answer:

1. n=\pm7

2. x=\pm7i[tex]3.[tex]\pm 12x =a

4. 22

Step-by-step explanation:

1. n^2 - 49 = 0

n^2 =49

n= \sqrt{49}

n=\pm7

2. x^2+64 = 0

x^2 =-64

x= \sqrt{49}

x=\pm7i[tex]3. Area of square = [tex]a^{2}

Where a is the side

We are given an area o square = 144x^{2}

So, 144x^{2}=a^{2}

\sqrt{144x^{2}}=a

\pm 12x =a

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So, in the given equation x^2 + z = 103

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

x^2 + 22 = 103

x^2 + 22 -103=0

x^2 -81=0

Thus the value of z is 22

8 0
3 years ago
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konstantin123 [22]
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(x+1)(x+2)
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