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kotykmax [81]
3 years ago
6

Kyle saves 8% of his income for a new car. This year his salary was $2,000 less than in the previous year, and he saved $3,000.

What was his salary in the previous year?
Mathematics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

let this previous income be x

then 8% of (x-2000) = 3000

     or, 8/100*(x-2000) = 3000

or, x - 2000 = 3000/0.08

or, x -2000 = 37500

x = 37500+2000 =39500 is his previous year salary

Step-by-step explanation:

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24 feet 9 inches

Step-by-step explanation:

14 ft + 9 ft = 23 ft

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23 feet + 1 ft + 9 in = 24 feet and 9 inches

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Perimeter = 2base + 2base
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How do you solve the following for x?
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Step-by-step explanation:

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Youssef can either way from his home to his workplace or ride his bicycle. he walks at a pace of 1 block per min, but he can tra
alex41 [277]

Youssef lives 15 blocks away from his work

<em><u>Solution:</u></em>

Given that Youssef can either way from his home to his workplace or ride his bicycle

Let "x" be number of blocks away from work Youssef works

<u><em>Case 1: walking</em></u>

He walks at a pace of 1 block per min

Therefore,

1 block = 1 minute

Thus to cross "x" blocks he takes "x" minutes

<em><u>Case 2: Bicycle</u></em>

He can travel 1 block in 20 sec on his bicycle

We know that,

To convert seconds to minute, divide the time value by 60

\rightarrow 20 seconds = \frac{20}{60} minutes = \frac{1}{3} minutes

Thus he takes 1/3 minutes for 1 block

So to cross "x" blocks he will take \frac{x}{3} minutes

Given that it takes youssef 10 min longer to walk to work than to ride his bike

This means difference between time taken to cross "x" blocks by walking and ride by bicycle is 10 minutes

\rightarrow x - \frac{x}{3} = 10\\\\\rightarrow \frac{3x - x}{3} = 10\\\\\rightarrow \frac{2x}{3} = 10\\\\\rightarrow x = \frac{30}{2}\\\\\rightarrow x = 15

Thus he lives 15 blocks away from his work

4 0
3 years ago
What is the factored form of y=x^3+3x^2-x-3 and what the zeros
PSYCHO15rus [73]
   y = x³ + 3x² - x - 3
   0 = x³ + 3x² - x - 3
   0 = x²(x) + x²(3) - 1(x) - 1(3)
   0 = x²(x + 3) - 1(x + 3)
   0 = (x² - 1)(x + 3)
   0 = (x² + x - x - 1)(x + 3)
   0 = (x(x) + x(1) - 1(x) - 1(1))(x + 3)
   0 = (x(x + 1) - 1(x + 1))(x + 3)
   0 = (x - 1)(x + 1)(x + 3)
   0 = x - 1    or    0 = x + 1    or    0 = x + 3
+ 1      + 1         - 1        - 1         - 3        - 3
   1 = x      or      -1 = x       or      -3 = x

Solution Set: {-3, -1, 1}
3 0
3 years ago
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