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Rainbow [258]
2 years ago
8

Solve step by step! Please answer correctly !!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Katen [24]2 years ago
7 0

Answer:

120°.

Step-by-step explanation:

If extend the line by the 50° and 90°, you form a triangle. They're alternate interior angles so the angle outside of the triangle at the left of the bottomost line is congruent to 150°. You then can subtract that from 180° to get the angle inside the triangle that's next to it, which gives you 30°. The 90° is also on the same like as one of the angles inside of the triangle, meaning together the two should equal 180°, making the angle inside the triangle 90° also. You then have 2 of the triangle's angles and can subtract the sum of them from 180° to get the 3rd angle of it (60°). That 3rd angle is on the same line to x, so 180°-60° should give you x, making x 120°, I think.

Colt1911 [192]2 years ago
3 0

Answer:

X is an acute angle, which means it is less than 90*, so it is probably 45*

Step-by-step explanation:

I was confused at first but then, I’m just like, I can solve this!

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An earthquake can be felt in a circular pattern from the epicenter. If the equation of this pattern is x2 + y2 = 2500, how many
kondor19780726 [428]
The radius of the circle ( which is the same as the distance from the epicenter) = square root of 2500  which is 50

Answer is 50 miles.
5 0
3 years ago
Read 2 more answers
Could someone help with the questions in the images below? I found them difficult
zubka84 [21]
Question 1a - You have got this correct, the median mark is 35
Question 1b- To work out the range, you must do the largest value subtract the smallest value. For your data, this would be 57 - 13 = 44

Question 2 - You have drawn the lines in the correct places, but you have not used a ruler. In order to get full marks on a question like this you must use a ruler.

Question 3 - Your lower quartile and median is correct, to find the upper quartile, we do 3(n/4). 'n' is the number of data points - in this case 120.
120/4 = 30
30 x 3 = 90
Go across the graph at 90 to see when the line is hit.
From what I can tell, the Upper Quartile is 3.

Next just find the maximum value.
Again, by the looks of it, the Maximum value is 8.5.

Now you have all the data needed for the box plot.

Min = 0
LQ = 0.8
Med = 2.1
UQ =  3
Max = 8.5

Using this information, draw a box plot like you did on the previous question.
<em>Again, I must stress that any line that you draw (unless purposely curved) must be drawn with a ruler; even on the graph at the top, during you working out. If you do not use a ruler, marks can be lost/taken away.</em>

Question 4a - For the median on a cumulative frequency chart, you must find the halfway point in the data. For this, we do n/2. In this case, n = 40
40/2 = 20
Draw a line (using  ruler) across at 20 until you reach the line.
Draw another one down to help you read the number.
The median looks like 34 seconds.
Question 4b - For this question, we already know the Min, Med and Max. Now we must work out the LQ and UQ.

Remember, LQ = n/4
In this case, n = 40
40/4 = 10
Look across at ten and you will find that the LQ = 16 seconds

To work out the UQ, we multiply the LQ place by 3 3(n/4).
3 x 10 = 30
30 on the graph takes us up to 45 seconds.

We now know that the:
Min = 9
LQ = 16
Med = 34
UQ = 45
Max = 57

With this information, draw a box plot like you have in the previous questions.

Question 5 - Good things to always compare on box plots are the Min/Max/Range and the Inter Quartile Range.
The boys had a lowest minimum and a higher maximum, this means that their range is larger, resulting in a large spread of data in comparison to the girls.
The Inter Quartile Range is the difference between the Upper Quartile and the Lower Quartile (how wide the box is).
The boy IQR = 45 - 16 = 29
The girls IQR = 34 - 23 = 11
Again, the girls have much more concise results; even though they did not get the quickest result, they were more like one another.

Question 5a - The median in a box plot is always the line down the centre of the box. In this case:
Median = 24 marks
Question 5b - The IQR is always the UQ - LQ
With this data, the IQR is the following:
36 - 17 = 19 marks

Hope this helps
6 0
3 years ago
Can someone explain how to get the answer?
Murljashka [212]
A = ((6 + 7 + 6) . 8)/2
A = 19 . 4
A = 76
6 0
2 years ago
Read 2 more answers
If the average of 3 numbers and 8 is 25 what is the sum of the three numbers
Gennadij [26K]
Let sum of 3 numbers be x.

Average of 3 numbers and 8 = \frac{x + 8}{4}

25 = \frac{x +8}{4}

100 = x +8

x= 92.

The sum of 3 numbers is 92.


3 0
3 years ago
Taylor does jumping jacks at a rate of 50 jumping jacks per minute. If Taylor completes her jumping jacks at a constant rate and
Viktor [21]

Answer:

3 minutes

Step-by-step explanation:

150/50

3 0
3 years ago
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