Question

A (-8,-6) b (-2,-6),c (-5,-4) reflection across the line x=1

Answer 1

The distance from $(h, k)$ to $x=1$ is $1-h$

To reflect across the line, we go twice this distance, which is $2-2h$

So the new x-coordinate is $h+(2-2h)=2-h$

$A (-8, -6)$ becomes $A' (2-(-8), -6)=(10, -6)$
$B (-2, -6)$ becomes $B' (2-(-2), -6)=(4, -6)$
$C (-5, -4)$ becomes $C' (2-(-5), -6)=(7, -6)$