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vazorg [7]
3 years ago
7

What is the surface area of the rectangular prism

Mathematics
2 answers:
iren2701 [21]3 years ago
6 0

Answer:

340

Step-by-step explanation:

first you have to find one side

i will go with 10 and 8

10*8=80

there are two of them

160 save this number in your bank

8*5=40 for the base

there are two of these too

80 save this number in your mental bank

for the last side 10 and 5

10*5=50 there are two of them

100

now add them all up

100+80+160=340

hope this helps!

anastassius [24]3 years ago
3 0

340 you were right

Step-by-step explanation:

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You’re rectangular 12 feet long and 8 feet wide. Your friend’s rectangular vegetable garden 50 feet long and 10 feet wide are th
igor_vitrenko [27]

Answer:

No

Step-by-step explanation:

For shapes to be similar, their ratios of length-to-length and width-to-width must be the same. When you divide the larger length by the smaller length and the larger width by the smaller width, do you get the same number? No, so these rectangles are not similar.

5 0
3 years ago
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Clara estimates that the length of a hiking trail is 5.75 km. She later learns that its actual length is 6.25 km. What is the pe
Hunter-Best [27]
Percent error : (approximate value - exact value) / exact value.....x 100

percent error : (5.75 - 6.25) / 6.25......ignore any negative signs
0.5 / 6.25 = 0.08.....x 100 = 8% error <==
8 0
3 years ago
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} &#10;
substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
Four different roads from Town A to Town B, and three different roads run from Town B to Town C. Two roads also run from Town A
LekaFEV [45]

Answer:

196

Step-by-step explanation:

To solve this, I broke it down into two parts.

A. Number of routes going to Town C

4 x 3 + 2 = 14

B. Number of routes going back to Town A

3 x 4 + 2 = 14

From here, it is easy to see what to do. Since there are 14 routes going to Town C and 14 routes going back, the answer is 14 x 14 = 196.

5 0
2 years ago
Someone help plss show work​
Mazyrski [523]

Answer:

Slope: \frac{3}{5}

Y-Intercept: (0,-5)

Step-by-step explanation:

1. To find the slope, we need to have the equation in slope-intercept form, which is y=mx+b. In this case, our equation is already in this form. m is what your slope is. In this case, our

2. To find the y-intercept we look at value b that is in y=mx+b. In this case, b is -5. So, our ordered pair is (0,-5).

4 0
2 years ago
Read 2 more answers
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