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AlladinOne [14]
3 years ago
13

Evaluate 6a-b^2/2 + (b/a)^2 if a = 2 and b = 4. 2 6 10.25 36

Mathematics
1 answer:
rodikova [14]3 years ago
4 0

\frac{6a -  {b}^{2} }{2}  +  \binom{b}{a}  ^{2}

a=2 b=4

\frac{6(2) -  {4}^{2} }{2}  +    \binom{4}{2}^{2}

\frac{12 - 16}{2}  +  \frac{16}{4}

\frac{ - 4}{2}  + 4

- 2 + 4 = 2

answer is option a 2

please mark this answer as brainlist

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Every 24 hours, Earth makes a full rotation around its axis. Earth's speed of rotation at the equator is 1.670 km per hour. What
Anna35 [415]

Answer:

The circumference of Earth's equator is 40,080 km.

Step-by-step explanation:

Given that every 24 hours, Earth makes a full rotation around its axis, and Earth's speed of rotation at the equator is 1,670 km per hour, to determine what is the circumference of Earth's equator the following calculation must be performed:

24 x 1,670 = X

40,080 = X

Therefore, the circumference of Earth's equator is 40,080 km.

3 0
2 years ago
In 1985, there were 285 cell phone subscribers in Arlington. The number of subscribers increased by 75% per year since 1985. Fin
ANTONII [103]

Answer:

The number of subscribers in 2008 is 110,845,988

Step-by-step explanation:

The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.

N(t) = N(0)(1+r)^{t}

And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.

In 1985, there were 285 cell phone subscribers in Arlington.

This means that N(0) = 285

The number of subscribers increased by 75% per year since 1985.

This means that r = 0.75

So

N(t) = 285(1.75)^{t}

Find the number of subscribers in 2008.

2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).

N(23) = 285(1.75)^{23} = 110,845,988

The number of subscribers in 2008 is 110,845,988

8 0
2 years ago
A car travels at an average speed of 56 miles per hour. How long does it take to travel 322 miles?
Goryan [66]

Answer:

5.75

Step-by-step explanation:

322/56=5.75

so the answer would be 5.75 or rounded up to 6

7 0
3 years ago
Read 2 more answers
completa con las razones trigonométricas de cada triángulo rectángulo dado y encuentra el lado faltante aplicando el teorema de
Rus_ich [418]

primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a

a=\sqrt[]{hipotenusa^2-cateto^2}a=\sqrt[]{100^2-85^2}=52.68

a=52.68 m

teniendo el lado faltante podemos calcular las razones trigonometricas

\sin (55)=\frac{85}{100}=0.85\cos (55)=\frac{52.68}{100}=0.52\tan (55)=\frac{85}{52.68}=1.61

\csc (55)=\frac{100}{85}=1.17\sec (55)=\frac{100}{52.68}=1.89\cot (55)=\frac{52.68}{85}=0.61

4 0
11 months ago
Solve the system of equations
Brums [2.3K]
5x+4y = 73
-4x + 4y = -8

5x + 4y -(-4x+4y) = 73 -(-8)
5x + 4y + 4x - 4y = 81
5x + 4x + 4y - 4y = 81
9x = 81
x = 81÷9
x = 9

Substitute x = 9 into any of the equations to find y.

5(9) + 4y = 73
45 + 4y = 73
4y = 73 - 45
4y = 28
y = 28÷4
y=7

Answers :
x = 9
y = 7
8 0
2 years ago
Read 2 more answers
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