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irakobra [83]
3 years ago
14

Use the following table to answer the question. Strong acids Weak acids Weak bases Strong bases HBr CH3COOH NH3 NaOH HNO3 HF NH4

OH KOH H2SO4 HCN Ca(OH)2 Which of these is a neutral salt? Na2SO4 NaCN KF (NH4)2SO4
Chemistry
2 answers:
Katyanochek1 [597]3 years ago
8 0
When a strong acid and strong base are combined, it forms a neutral salt. Therefore, Na₂SO₄ is a neutral salt because it is the product of NaOH (a strong base) and H₂SO₄ (a strong acid).
allsm [11]3 years ago
7 0
The answer is A Na2SO<span>4 just finished the quiz, good luck!</span>
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Why is it not possible to just consume only pure ATP and thus eliminate some steps in
xeze [42]

Our digestive has the steps of digestion and absorption associated with it. So all the compounds taken in as food are first broken down into simpler components before absorption.

<h3><u>Explanation:</u></h3>

ATP or Adenosine Triphosphate is a compound containing a molecule of adenine as nitrogen base, a ribose sugar and three molecules of phosphate attached with the adenine in a chain. Its unable to get absorbed into the system as ATP itself. In intestine, it will be broken down into Adenine, ribose, and phosphates and then absorbed individually into blood.

Thus even if we consume raw ATP, we can't bypass the process of ATP formation. So, there's no significance. And secondly, ATP is very expensive and not suitable for consumption itself.

4 0
3 years ago
The dimensions of a rectangular solid are measured to be 1.27 cm, 1.3 cm, and 2.5 cm. The volume should be recorded as
meriva

Answer: 4.1 cm3

Explanation:

5 0
3 years ago
Calculate the amount of time required to raise temperature of 0.50 liter of water from
Burka [1]
<h3>Answer:</h3>

19 seconds

<h3>Explanation:</h3>

Heat energy was supplied and used to heat 0.50 liters of water from 0°C to 10°C.

This means water gained heat energy that was supplied.

Therefore;

Heat supplied = Heat gained by water

We are required to calculate the time taken to raise the temperature of water from 0°C to 10°C.

Step 1: Calculate the heat gained by water

Quantity of heat = Mass × specific heat capacity × change in temperature

Density of water 1 g/ml

Volume of water is 500 mL

Therefore, since Mass = density × volume

The mass of water = 500 g

Change in temperature = 10° C

Specific heat capacity of water = 4.18 J/g/°C

Thus;

Quantity of heat = 500 g × 4.18 J/g/°C × 10

                           = 20,900 Joules

Step 2: Heat supplied by a heater

Heat supplied = Power × time

Power = 1100 J/s

Assuming the time required is x

Heat supplied = 1100x Joules

Step 3: Time required

Remember; heat supplied = heat gained by water

Therefore;

1100x joules = 20,900 Joules

      x = 20,900/1100

        = 19 seconds

Therefore, the time required to raise the temperature of water from 0°C to 10°C is 19 seconds.

6 0
3 years ago
Which type of matter tends to become LESS soluble in water as the temperature rises? *
Kisachek [45]
B.liquids thanks have a great day
8 0
4 years ago
A mixture contains only NaCl and Al2(SO4)3. A 1.45-g sample of the mixture is dissolved in water, and an ex- cess of NaOH is add
chubhunter [2.5K]

Answer:

The mass percent of aluminum sulfate in the sample is 16.18%.

Explanation:

Mass of the sample = 1.45 g

Al_2SO_3+6NaOH\rightarrow 2Al(OH)_3+3Na_2SO_4

Mass of the precipitate = 0.107 g

Moles of aluminum hydroxide = \frac{0.107 g}{78 g/mol}=0.001372 mol

According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .

Then 0.001372 moles of aluminum hydroxide will be obtained from:

\frac{1}{2}\times 0.001372 mol=0.000686 mol

Mass of 0.000686 moles of aluminum sulfate :

= 0.000686 mol × 342 g/mol = 0.2346 g

The mass percent of aluminum sulfate in the sample:

=\frac{ 0.2346 g}{1.45g}\times 100=16.18\%

5 0
3 years ago
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