The choices are:
<span>A. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0</span>°<span>C.
B. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 298 K.
C. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 273</span>°<span> C.
D. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 100</span>°<span> C.
The correct answer is A because the two gases will have the same temperature and 273 K = 0</span>°C
Answer:
the water concentration at equilibrium is
⇒ [ H2O(g) ] = 0.0510 mol/L
Explanation:
- CH4(g) + H2O(g) ↔ CO(g) + 3H2(g)
∴ Kc = ( [ CO(g) ] * [ H2 ]³ ) / ( [ CH4(g) ] * [ H2O(g) ] ) = 0,30
⇒ [ CO(g) ] = 0.206 mol / 0.778 L = 0.2648 mol/L
⇒ [ H2(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L
⇒ [ CH4(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L
replacing in Kc:
⇒ ((0.2648) * (0.2404)³) / ([ H2O(g) ] * 0.2404 ) = 0.30
⇒ 0.0721 [ H2O(g) ] = 3.679 E-3
⇒ [ H2O(g) ] = 0.0510 mol/L
Answer:
The statement d) is true: The entropy of the universe is always increased in a spontaneous process.
Explanation:
a), b), c) and e) are false.
a) When no heat exchange occurs between the system and its surroundings
, this process is called an adiabatic process. Because the system does work on the surroundings, w is a negative quantity and there is a decrease in the system’s internal energy (since it cannot exchange heat, it will have to use its internal energy to do work).
b) Breaking a bond will always require energy, whereas forming a bond releases energy. Therefore, if more bonds are broken than formed, the enthalpy of a reaction will be positive.
c) The second law of thermodynamics states that the entropy of the universe increases in a spon
taneous process and remains unchanged in an equilibrium process. Therefore, the entropy of the universe is not always constant.
d) True.
e) According to the Gibbs equation, if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS is smaller in magnitude than ΔH. This condition is met when T is small.
Answer:
the pasta will soften
Explanation:
the pasta will boil and will soften up as a result of it being regular pasta
Most likely White or another color that appears "bright" to us, such as gold, silver, yellow, pink, or sometimes green. Hope it helped!