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gizmo_the_mogwai [7]
3 years ago
10

An elevator cab has a mass of 4710 kg and can carry a maximum load of 1910 kg. If the cab is moving upward at full load at 3.80

m/s, what power is required of the force moving the cab to maintain that speed?
Physics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

Power P=246.78 KW

Explanation:

Mass of Elevator=4710 Kg

Can carry load =1910 Kg

Total Mass m to be lifted =4710 kg + 1910 Kg =6620 kg

speed = 3.80 m/s ⇒ per second distance traveled (height h) = 3.80 m  and    time t = 1 s

Using formula of Power P = \frac{work}{time}

P = \frac{mgh}{t}

P= 6620kg × 9.81 m/s² × 3.80 m / 1s

P= 246780.36 W

P=246.78 KW

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how many bits are required to sample an incoming signal 4000 times per second using 64 different amplitude level
Gelneren [198K]

Answer:

6 bits

Explanation:

The quality of digitized signal can be improved by reducing quantizing error. This is done by increasing the number of amplitude levels, thereby minimizing the difference between the levels and hence producing a smoother signal.

Also, Sampling frequently (also known as oversampling) can help in improving signal quality.

To get the number of bits, we use:

2ⁿ = amplitude level

where n is the number of bits.

Given an amplitude level of 64, hence:

2ⁿ = 64

2ⁿ = 2⁶

n = 6 bits

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