Hey there,
Your question states: <span>The area on a wall covered by a rectangular poster is 294 square inches. The length of the poster is 1.5 times longer than the width of the poster. What are the dimensions of the poster? </span>
Your correct answer would be
Hope this helps.
Answer:
2/5 because there is 5 spots and A is the second one on the number line
2 minutes = 1.20 dollars for price of sundae.in 4 hours how many minutes are there?=> 60 * 4 hours = 240 minutes => 240 / 2minutes per sundae = 120 minutes => 120 * 1.20 = 144 dollars in 4 hoursOr 72 dollars in 2 hours
Answer:
d. 46.19
Step-by-step explanation:
y=124.85(0.37)
to figure out the percent decrease, subtract the percent from 100. then divide by 100 to get a decimal. multiply that decimal by the original cost to get the answer.
Answer: The mean and standard deviation are 567.2 and 89.88 resp.
Step-by-step explanation:
Since we have given that
For 370 parts per million = 7% = 0.07
For 440 parts per million = 10% = 0.10
For 550 parts per million = 49% = 0.49
For 670 parts per million = 34% = 0.34
So, Mean of the carbon dioxide atmosphere for these trees would be
![E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D370%5Ctimes%200.07%2B440%5Ctimes%200.1%2B550%5Ctimes%200.49%2B670%5Ctimes%200.34%3D567.2)
And
![E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3D370%5E2%5Ctimes%200.07%2B440%5E2%5Ctimes%200.1%2B550%5E2%5Ctimes%200.49%2B670%5E2%5Ctimes%200.34%3D329794)
So, Variance would be
![Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16](https://tex.z-dn.net/?f=Var%5C%20x%3DE%5Bx%5E2%5D-E%5Bx%5D%5E2%3D329794-567.2%5E2%3D8078.16)
So, the standard deviation would be
Hence, the mean and standard deviation are 567.2 and 89.88 resp.
