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Svet_ta [14]
3 years ago
12

What is the domain and range of y=x^2?

Mathematics
2 answers:
babunello [35]3 years ago
8 0

Answer:

the domain is all real numbers, and the range is y>=0.

Step-by-step explanation:

r-ruslan [8.4K]3 years ago
3 0
Hi there! the best way of solving this is picturing out what the graph might look like. Let's assume you had the graph of a parabola y=x^2. You know that for every x you substitute, there'd always be a value for y. Thus, the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. The range on the other hand is different. We know that any number raised to the second power will always yield a positive integer or 0. Thus, y=x^2 won't have any negative y-values as the graph opens upward. Therefore, the range is: ALL REAL NUMBERS GREATER THAN OR EQUAL TO 0. or simply: 0 to +INFINITY. 

<span>On the other hand, a cubic function y=x^3 is quite different from the parabola. For any x that we plug in to the function, we'd always get a value for y, thus there are no restrictions. And the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. For the y-values, the case would be quite similar but different to that of the y=x^2. Since a negative number raised to the third power gives us negative values, then the graph would cover positive and negative values for y. Thus, the range is ALL REAL NUMBERS or from -INFINITY to + INFINITY. Good luck!!!:D</span>
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Find the value of c so that (x+2) is a factor of the polynomial<br><br> p(x)=3x^4-x^2+cx-2
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Using polynomial long division, we get
         
         3x^3+6x^2+11x
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If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.

For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
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4 0
3 years ago
If T is the midpoint of SU, find the values of x and ST
tatiyna

T is the midpoint of the line, meaning that in line SU, line ST and line TU are of equal length, since T is at the middle of the line.

9x=4x+25

5x=25

x=5

ST=9x

ST=9*5

ST=45

Hope this helps. 頑張って!

8 0
3 years ago
Read 2 more answers
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