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Svet_ta [14]
3 years ago
12

What is the domain and range of y=x^2?

Mathematics
2 answers:
babunello [35]3 years ago
8 0

Answer:

the domain is all real numbers, and the range is y>=0.

Step-by-step explanation:

r-ruslan [8.4K]3 years ago
3 0
Hi there! the best way of solving this is picturing out what the graph might look like. Let's assume you had the graph of a parabola y=x^2. You know that for every x you substitute, there'd always be a value for y. Thus, the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. The range on the other hand is different. We know that any number raised to the second power will always yield a positive integer or 0. Thus, y=x^2 won't have any negative y-values as the graph opens upward. Therefore, the range is: ALL REAL NUMBERS GREATER THAN OR EQUAL TO 0. or simply: 0 to +INFINITY. 

<span>On the other hand, a cubic function y=x^3 is quite different from the parabola. For any x that we plug in to the function, we'd always get a value for y, thus there are no restrictions. And the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. For the y-values, the case would be quite similar but different to that of the y=x^2. Since a negative number raised to the third power gives us negative values, then the graph would cover positive and negative values for y. Thus, the range is ALL REAL NUMBERS or from -INFINITY to + INFINITY. Good luck!!!:D</span>
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Step-by-step explanation:

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2 years ago
What is an equation parallel to y=3x-5
choli [55]

Answer:

ANY line that has a slope of 3, and any y intercept other than -5.

Step-by-step explanation:

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here are a few examples:

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3 years ago
What is the sum? -1.5 + 1.9​
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Step-by-step explanation:

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3 years ago
Write the equation of a line that is perpendicular to y=-0.3x+6 and that passes through the point (3,-8)
MariettaO [177]
Hey there!

First, let's look at what perpendicular means. Imagine a cross, where there's all 90 degree angles. That's exactly what we're talking about when we say perpendicular. The given equation is in slope-intercept form, where we have:

y = mx + b
where m is the slope and b is the y-intercept.

When we're writing an equation with a perpendicular slope, we use the negative reciprocal of the given slope. Thus, we can make 0.3 1/3, and take the reciprocal to make 3, and make it negative 3 as it's the negative reciprocal. Now, we know we have a line with the slope of -3 and goes through (-3, 8). We can use the x and y values in this set of points, along with the slope, to create an equation to solve for b. That gives us:

8 = -3(-3) + b
8 = -9 + b
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Now, since we have slope and y-intercept, we can write our equation as:

y = -3x + 17

Hope this helps!
5 0
3 years ago
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