The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
Which point on the y-axis lies on the line that passes through point C and is perpendicular to line AB?
A. (-6, 0)
B. (0, -6)
C. (0, 2)
D. (2, 0)
The graph of the question is attached.
Answer:
The point is (x, y) = (0, 2)
The correct option is C.
Therefore, the point (0, 2) on the y-axis lies on the line that passes through point C and is perpendicular to line AB.
Step-by-step explanation:
From the given graph, the points A and B are
![(x_1, y_1) = (-2, 4) \\\\(x_2, y_2) = (2,-8) \\\\](https://tex.z-dn.net/?f=%28x_1%2C%20y_1%29%20%3D%20%28-2%2C%204%29%20%5C%5C%5C%5C%28x_2%2C%20y_2%29%20%3D%20%282%2C-8%29%20%5C%5C%5C%5C)
The slope of the equation is given by
![m_1 = \frac{-8 - 4 }{2 -(-2)} \\\\ m_1 = \frac{-12 }{2+2} \\\\m_1 = \frac{-12 }{4} \\\\m_1 = -3 \\\\](https://tex.z-dn.net/?f=m_1%20%3D%20%5Cfrac%7B-8%20-%204%20%7D%7B2%20-%28-2%29%7D%20%5C%5C%5C%5C%20m_1%20%3D%20%5Cfrac%7B-12%20%7D%7B2%2B2%7D%20%5C%5C%5C%5Cm_1%20%3D%20%5Cfrac%7B-12%20%7D%7B4%7D%20%5C%5C%5C%5Cm_1%20%3D%20-3%20%5C%5C%5C%5C)
We know that the slopes of two perpendicular lines are negative reciprocals of each other.
![m_2 = - \frac{1}{m_1}](https://tex.z-dn.net/?f=m_2%20%3D%20-%20%5Cfrac%7B1%7D%7Bm_1%7D)
So the slope of the other line is
![m_2 = \frac{1 }{3} \\\\](https://tex.z-dn.net/?f=m_2%20%3D%20%5Cfrac%7B1%20%7D%7B3%7D%20%5C%5C%5C%5C)
Now we can find the equation of the line that is perpendicular to the line AB and passes through the point C.
From the graph, the coordinates of point C are
![(x_1, y_1) = (6, 4)](https://tex.z-dn.net/?f=%28x_1%2C%20y_1%29%20%3D%20%286%2C%204%29)
The point-slope form is given by,
![y - y_1 = m(x -x_1)](https://tex.z-dn.net/?f=y%20-%20y_1%20%3D%20m%28x%20-x_1%29)
Substitute the value of slope and the coordinates of point C
![y - 4 = \frac{1 }{3} (x - 6)\\\\](https://tex.z-dn.net/?f=y%20-%204%20%3D%20%5Cfrac%7B1%20%7D%7B3%7D%20%28x%20-%206%29%5C%5C%5C%5C)
To get the y-intercept, substitute x = 0
![y - 4 = \frac{1 }{3} (0 - 6) \\\\y - 4 = \frac{-6 }{3}\\\\y - 4 = -2\\\\y = 4 -2 \\\\y = 2 \\\\](https://tex.z-dn.net/?f=y%20-%204%20%3D%20%5Cfrac%7B1%20%7D%7B3%7D%20%280%20-%206%29%20%5C%5C%5C%5Cy%20-%204%20%3D%20%5Cfrac%7B-6%20%7D%7B3%7D%5C%5C%5C%5Cy%20-%204%20%3D%20-2%5C%5C%5C%5Cy%20%3D%204%20-2%20%5C%5C%5C%5Cy%20%3D%202%20%5C%5C%5C%5C)
So, the point is
![(x, y) = (0, 2)](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%280%2C%202%29)
The correct option is C.
Therefore, the point (0, 2) on the y-axis lies on the line that passes through point C and is perpendicular to line AB.