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xenn [34]
3 years ago
8

What information would you find in an address book

Computers and Technology
2 answers:
Anton [14]3 years ago
7 0

email address is the correct answer

Vlad [161]3 years ago
5 0

names, phone numbers, address for sure, emails, and etc..

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interpret the following SQL create table persons (person I'd int, last name varchar (255) first name varchar (255) address varch
zhuklara [117]

Answer:

Kindly check explanation

Explanation:

The SQL statement above could be interpreted as follows :

create table command is used to create a table named 'persons' with five columns which are labeled :

person I'd : whose data type is an integer

last name column with a variable character data type with maximum length of 255

first name column with a variable character data type with maximum length of 255

address column with a variable character data type with maximum length of 255

city column with a variable character data type with maximum length of 255

The VARCHAR data type is ideal since we expect the column values to be of variable length.

3 0
3 years ago
Write a C++ program that reads students' names followed by their test scores. The program should output each students' name foll
Mashutka [201]

Answer:

#include<iostream>

#include<conio.h>

using namespace std;

struct studentdata{

char Fname[50];

char Lname[50];

int marks;

char grade;

};

main()

{

studentdata s[20];

for (int i=0; i<20;i++)

   {

cout<<"\nenter the First name of student";

cin>>s[i].Fname;

cout<<"\nenter the Last name of student";

cin>>s[i].Lname;

cout<<"\nenter the marks of student";

cin>>s[i].marks;

}  

 

for (int j=0;j<20;j++)

{

if (s[j].marks>90)

{

 s[j].grade ='A';

}

else if (s[j].marks>75 && s[j].marks<90)

{

   s[j].grade ='B';

}

else if (s[j].marks>60 && s[j].marks<75)

{

 s[j].grade ='C';

}

else

{

 s[j].grade ='F';

}

}

int highest=0;

int z=0;

for (int k=0;k<20; k++)  

{

if (highest<s[k].marks)

{

 highest = s[k].marks;

 z=k;

}

 

}

cout<<"\nStudents having highest marks"<<endl;

 

cout<<"Student Name"<< s[z].Fname<<s[z].Lname<<endl;

cout<<"Marks"<<s[z].marks<<endl;

cout<<"Grade"<<s[z].grade;

getch();  

}

Explanation:

This program is used to enter the information of 20 students that includes, their first name, last name and marks obtained out of 100.

The program will compute the grades of the students that may be A,B, C, and F. If marks are greater than 90, grade is A, If marks are greater than 75 and less than 90, grade is B. For Mark from 60 to 75 the grade is C and below 60 grade is F.

The program will further found the highest marks and than display the First name, last name, marks and grade of student who have highest marks.

6 0
3 years ago
3) An algorithm has a run time of O(nk ) for some integer k. On an input of size 500, the algorithm takes 16 seconds to run. On
lukranit [14]

Answer:

The value of k is 4

Explanation:

Solution

Given that:

k = integer

Input size = 500

The algorithm takes a run of = 16 seconds

Input size = 750

The algorithm takes a run of = 81 seconds

Now,

We have to determine the value of k

The equation is shown below:

(500)^k /16 = (750) ^k /81

Thus

(750/500)^ k = 81/16

= (3/2)^k

=(3/2)^ 4

k is = 4

6 0
3 years ago
Solve this for brainlest​
saw5 [17]

Answer:

which chapter is this

Explanation:

6 0
3 years ago
A web page that allows interaction from the user​
kirill115 [55]

Answer:

Its A Dynamic Web Page

Explanation:

5 0
3 years ago
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