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Goryan [66]
3 years ago
9

Why is a 99 confidence interval wider than a 95 confidence interval?

Mathematics
1 answer:
Ugo [173]3 years ago
4 0
A larger interval is wider than a smaller interval.
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A particle moves with velocity function v(t) = 2t^2 - 3t - 3, with v measured in feet per second and t measured in seconds. Find
SashulF [63]
V(t) = 2t^2 - 3t - 3

for an acceleration a(t),
a(t) = d (v(t)) / d t
a(t) = 4t - 3

at t=2
a(2) = 8 - 3
a(2) = 5 feet/s^2

3 0
3 years ago
Simplify y÷4.5+1.69=9.52
grandymaker [24]
1 Simplify
4
.
5
+
1
.
6
9
4.5+1.69 to
6
.
1
9
6.19.
6
.
1
9
=
9
.
5
2
6.19=9.52

2 Since
6
.
1
9
=
9
.
5
2
6.19=9.52 is false, there is no solution.
No Solution

Done
4 0
3 years ago
Read 2 more answers
Note: You may use a calculator to solve the following problems.
Verizon [17]
Use a calculator it will help.
4 0
3 years ago
Select transform to change the drawing of the figure. Which expression could be used to find the combined area of the right and
Tems11 [23]

Answer: B aka (3’2) + (3’2)

Step-by-step explanation:

I got it right on Edge 2021, good luck! Also if right, can you please mark Brainliest?

4 0
3 years ago
What’s the distance formula
Whitepunk [10]

Step-by-step explanation:

\text{Let}\ A(x_1,\ y_1)\ \text{and}\ B(x_2,\ y_2).\ \text{Then the distance between}\ A\ \text{and}\ B\ \text{is:}\\\\|AB|=\sqrt{(x_2-x_1)^2+(y_2-y1)^2}\\\\Example:\\\\A(2,\ 5),\ B(-1,\ 1)\\\\|AB|=\sqrt{(-1-2)^2+(1-5)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

7 0
3 years ago
Read 2 more answers
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