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blagie [28]
3 years ago
9

Stop 1: first, let's pay the bills.

Mathematics
2 answers:
xeze [42]3 years ago
5 0

Answer:

525 Minutes

Step-by-step explanation:

The equation would be...

$60 + $0.12m = $123

Now we can simplify

($60 - $60) + $0.12m = ($123 - $60)

$0.12m = $63

($0.12m/$0.12) = ($63/$0.12)

M = 525

fgiga [73]3 years ago
4 0
123-60=63 63/.12=525 minutes
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Find three solutions for this linear function and choose the correct graph by clicking on it. F -1(x) if F(x) = x + 3
algol13

Answer:

[1,2], [2,1], [3,0]

Step-by-step explanation:

To find F-1(x) if F(x)=x+3 we just need to put -x instead of x.

From our graph(attached) we multiply any three solutions by a -1:

F-1(x)\\\\#For \ x=1\\F-1(1)=-1+3=2\\\\#For \ x=2\\F-1(2)=-2+3=1\\\\#For \ x=3\\F-1(3)=-3+3=0

Hence, the 3 solutions are [1,2],[2,1],[3,0]

3 0
3 years ago
I'm stuck on this question help!
Vadim26 [7]
1500 is your answer hope it helps

6 0
3 years ago
What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?
notsponge [240]

x^2+bx+c will have real roots when the discriminant of the quadratic, \Delta=b^2-4c, is non-negative, i.e.

b^2-4c\ge0\implies b^2\ge4c

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking b,c at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both b,c are chosen indepently of one another from [0, 1]. Let B,C denote the random variables that take on the values of b,c, respectively. I'll assume B,C are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

f_X(x)=\begin{cases}1&\text{for }0

F_X(x)=\begin{cases}0&\text{for }x

where X is either of B,C.

Then the question is to find P(B^2\ge4C). We have

P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)

and we can condition the random variable C on the event of B=b by supposing

P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)

then integrate over all possible values of b.

=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}

4 0
3 years ago
A linear equation is any equation with a constant rate of change (slope)?
denis-greek [22]

Answer:

I believe that is correct. But there are other ways to define a linear equations along with this one :)

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3 pans. If she wants 12 servings for every 5 people and there are 10 people coming then she will need 24 servings. 24 divided by 8 is 3.

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