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3 years ago

A linear equation is any equation with a constant rate of change (slope)?

Mathematics

1 answer:

denis-greek [22]3 years ago

6 0

Answer:

I believe that is correct. But there are other ways to define a linear equations along with this one :)

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Stan made 24 sales in 6 hours . what is the ratio of sales to hours?

Furkat [3]

Let s = sale

Let h = hours

The ratio is s to h, which can be written as a fraction as 24/6.

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3 years ago

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A farmer had a farm with animals.

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Answer: Part B

Step-by-step explanation:

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Part B if the height of each prism is 10 Cm what is the surface area prism

Evgen [1.6K]

Answer:

Prism A:

$Area = 288cm^2$

Prism B:

$Area =250cm^2$

Step-by-step explanation:

Given

See attachment for prisms

$Height(h) = 10cm$

Required

Determine the surface area of both prisms

Prism A is triangular and as such, the surface area is:

$Area = 2 * A_b + (a + b + c) * h$

Where

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

and

$s = \frac{a + b + c}{2}$

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

$a = 8; b =6; c =10$

So, we have:

$s = \frac{a + b + c}{2}$

$s = \frac{8 + 6 + 10}{2}$

$s = \frac{24}{2}$

$s = 12$

Also:

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

$A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}$

$A_b = \sqrt{576}$

$A_b = 24$

So:

$Area = 2 * A_b + (a + b + c) * h$

$Area = 2 * 24 + (8 + 6 + 10) * 10$

$Area = 288cm^2$

Prism B is a rectangular prism. So, the area is calculated as:

$Area = 2 * (ab + bh + ah)$

From the attachment

$a = b = 5$

$h =10$

So:

$Area =2 * (5 * 5 + 5 * 10 + 5 * 10)$

$Area =250cm^2$

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2 years ago

Which best describes a scalene triangle?

FinnZ [79.3K]

Answer:

All three sides of the triangle are different lengths.

Step-by-step explanation:

hope this helps :)

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3 years ago

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I NEED HELP ASAP PLEASE!! I WILL AWARD BRAINLIEST

Irina-Kira [14]

9514 1404 393

Answer:

x ≥ 7
54 -6m
y -x

Step-by-step explanation:

You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.

108. |x -7| = x -7 . . . . . true for x-7≥0

x ≥ 7 . . . . makes the statement true

1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:

54 -6m . . . . . simplified form for m < 9

1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive

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3 years ago