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3 years ago

13

-6=-8+

{11} " align="absmiddle" class="latex-formula">

1 answer:

vekshin13 years ago

8 0

P=22 rewrite the question as -8+p/11=-6 then move all terms not containing p to the right side p/11=2 multiply both sides of the given equation by 11, the reciprocal, 11*p/11=11*2

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ziro4ka [17]

The linear equation that has a slope of -7 and crosses the x-axis at (3, 0) is:

y = -7x + 21

<h3>How to find the linear equation?</h3>

A general linear equation is:

y = a*x +b

Where a is the slope and b is the y-intercept.

The slope must be equal to the limit found in part a, and you say that it is equal to -7, so the slope is -7. And for how is written the problem, I understand that it crosses the x-axis at x = 3.

Then we will have:

y = -7*x + b

Such that, when x = 3, y = 0, then:

0 = -7*3 + b

21 = b

Then the linear equation is y = -7x + 21

If you want to learn more about linear equations:

brainly.com/question/1884491

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3 0

2 years ago

Find the equation of the line perpendicular to y =<br> 3x + 6 and containing the point (-9,-5).

neonofarm [45]

The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is $y = \frac{-1}{3}x - 8$

<em><u>Solution:</u></em>

Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that <em>product of slopes of given line and slope of line perpendicular to given line is equal to -1</em>

Slope of given line $\times$ slope of line perpendicular to given line = -1

$3 \times \text{ slope of line perpendicular to given line }= -1$

$\text{ slope of line perpendicular to given line } = \frac{-1}{3}$

Let us now find the equation of line with slope $m = \frac{-1}{3}$ and containing the point (-9, -5)

Substitute $m = \frac{-1}{3}$ and (x, y) = (-9, -5) in eqn 1

$-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8$

<em><u>Thus the required equation of line is:</u></em>

Substitute $m = \frac{-1}{3}$ and c = -8 in eqn 1

$y = \frac{-1}{3}x - 8$

Thus the required equation of line perpendicular to given line is found

6 0

3 years ago

( − 35 − 42 − 63 ) ∶ ( + 7 )

olga nikolaevna [1]

(-35-42-63)/7= (-140)/7=-20

7 0

2 years ago

Say the fraction in unit form. 1/10

Anni [7]

Answer:

One tenth

Step-by-step explanation:

You state the number on top as is.

Numerator:

1 - one

2- two

and so on.

over the denominator

which you state as an ordinal number

2 = halves

3 = thirds

4 = fourths

5 = fifths

etc.

so 1/10 would be one over tenths but you say one tenth.

5 0

3 years ago

Translate the word phrase into a variable expression.

UNO [17]

The answer is b x/3-8

5 0

3 years ago