Ask question

Ask question

All categories

3 years ago

13

-6=-8+

{11} " align="absmiddle" class="latex-formula">

1 answer:

vekshin13 years ago

8 0

P=22 rewrite the question as -8+p/11=-6 then move all terms not containing p to the right side p/11=2 multiply both sides of the given equation by 11, the reciprocal, 11*p/11=11*2

You might be interested in

Please help me do this problem. 20 points to the first one that helps me with these 2. I am very desperate.

MAVERICK [17]

Answer:

here's your answer:

Triangle ABC has vertices A(0,0), B(0,4), and C(3,0). Write the equation for the line containing altitude AR in standard...

brainly.com/question/8243985?utm_source=android&utm_medium=share&utm_campaign=question

4 0

3 years ago

What are the solutions to the expression 4x2+11x−3

lina2011 [118]

Step-by-step explanation:

4x² + 11x - 3 = 0

(4x-1)(x+3) = 0

x = 1/4, -3

6 0

3 years ago

Read 2 more answers

A student earned 50% on a 100 question quiz. How many questions did

aleksandr82 [10.1K]

Answer:

50

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Austin buys $10 worth of food for his dog each week. There are 52 weeks in a year.

ololo11 [35]

Answer:

b i think

Step-by-step explanation:

8 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer

lyudmila [28]

If

$f(\theta)=10\cos\theta+5\sin^2\theta$

then the derivative is

$f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta$

Critical points occur where $f'(\theta)=0$ . This happens for

$-10\sin\theta+10\sin\theta\cos\theta=0$

$-10\sin\theta(1-\cos\theta)=0$

$\implies-10\sin\theta=0\text{ or }1-\cos\theta=0$

In the first case, we find

$-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi$

In the second,

$1-\cos\theta=0\implies\cos\theta=1\implies\theta=2n\pi$

So all the critical points occur at multiples of $\pi$ , or $n\pi$ . (This includes all the even multiples of $\pi$ .)

3 0

3 years ago