Answer:
8x+y-13=0
Step-by-step explanation:
let the given point be
A(1,5)=(x1,y1)
slope(m)= -8
then,equation of straight line is,
(y-y1)=m(x-x1)
(y-5)= -8(x-1)
y-5= -8x+8
8x+y-5-8=0
therefore,8x+y-13=0 ..........(i) is the required equation.
Answer:
B. approximately 7 calories
Step-by-step explanation:
got it right, hope you do as well
The complete question in the attached figure
we know that
(see the attached figure n 2 to understand the problem)[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy
now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy
we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.
the answer is
</span>
JD should also subtract the areas of eight hidden surfaces<span>
</span>
Answer:
Step-by-step explanation:
Scale= length on drawing / actual length
Let the actual length b x
3:10=2/5/x
3/10=2/5x
Cross multiply
15x=20
x=4/3
The actual length is 4/3
C can be found using pythagoras theorem. c2=a2+b2. Now, b is not given, but we know that cos(theta)=b/c=>b=c*cos(theta). Substituting b in the above relation, c2=a2+c2(cos(theta))^2=>c2=a2/(1-cos((theta))^2). c is the squareroot of c2. Hence c=sqrt(2/(1-cos((theta))^2))