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Hoochie [10]
3 years ago
5

Box of 12 golf balls costs $45. what is the unit rate

Mathematics
1 answer:
nevsk [136]3 years ago
5 0
$3.75 per golf ball...............
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4% of a number is what fraction of that number?
Brut [27]

Answer:

1/25 or 4/100

Step-by-step explanation:

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Ratio equivalent to 1:7.
diamong [38]

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49

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4 0
3 years ago
Which value is a solution of the equation 3 - 2x=-5?<br> 02<br> 04<br> 0-2<br> 01/5
Vikki [24]
Answer: 04
Explanation: We are given 3-2x=-5. We would subtract 3 from both sides. The equation would then look like this after subtraction from both sides: -2x=-8. We would then divide -2 by both sides so we can isolate the variable. The equation would look like this x=4.
3-2x=-5
-2x=-8
x=4
6 0
2 years ago
Read 2 more answers
A sneaker company can make 50 pairs of sneakers for every 6 yards of material. Make a table to show the relation between materia
Law Incorporation [45]

A sneaker company can make 50 pairs of sneakers for every 6 yards of material.

Then in each case you can consider proportion.

1. 50 pairs -- 6 yards,

80 pairs -- x yards.

Mathematically,

\dfrac{50}{80}=\dfrac{6}{x},\\ \\x=\dfrac{80\cdot 6}{50}=9.6\ yards.

2. 50 pairs -- 6 yards,

100 pairs -- x yards.

Mathematically,

\dfrac{50}{100}=\dfrac{6}{x},\\ \\x=\dfrac{100\cdot 6}{50}=12\ yards.

3. 50 pairs -- 6 yards,

120 pairs -- x yards.

Mathematically,

\dfrac{50}{120}=\dfrac{6}{x},\\ \\x=\dfrac{120\cdot 6}{50}=14.4\ yards.

4. 50 pairs -- 6 yards,

140 pairs -- x yards.

Mathematically,

\dfrac{50}{140}=\dfrac{6}{x},\\ \\x=\dfrac{140\cdot 6}{50}=16.8\ yards.

Thus, the table is

\begin{array}{cc}\text{Pairs}&\text{Yards}\\50&6\\80&9.6\\100&12\\120&14.4\\140&16.8\end{array}

The domain of the relation is the set \{50,80,100,120,140\} and the range of the relation is \{6,9.6,12,14.4,16.8\}.See attached diagram for the graph of the relation.

4 0
3 years ago
the cost of plastering a wall of a room having length 8m and heights 4m at Rs 15 per m² is Rs 1560 . find the cost of carpeting
Effectus [21]

Step-by-step explanation:

here ,

length = 8m

height=4m

Rate of plastering 4 walls = 15/m^2

Cost of plastering 4 wall = Rs 1560

Area of floor = Cost of plastering / Rate of plastering

= 1560/15

= 104

again,

Area of four wall = 2h(l+b)

or, 104= 2×4(8+b)

or, 104 =8(8+b)

or, 104/8=8+ b

or,13 - 8= b

or, b= 5

again,

Area of floor= l×b

= 8×5

= 40

again,

Rate of carpeting the floor= 300/ m^2

Area of floor = 40 m^2

cost of carpeting=Rate × Area

= 300×40

= 12000

4 0
3 years ago
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