If (6^0)^x = 1 , what are the possible values of x? Explain your answer. (5 points)
2 answers:
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Answer:
Step-by-step explanation:
Given that,
A sequence 352,345,338.
First term = 352
Common difference = 345-352 = -7
We need to find the 37th term of the sequence.
The nth term of an AP is given by :
So, the 37th term of the sequence is 100.
It's a linear function. We need only two points to draw a graph.
We choose any values of x and calculate the value of y.
for x= 0 → y = 3(0) - 1 = 0 - 1 = -1 → (0, -1)
for x = 2 → y = 3(2) - 1 = 6 - 1 = 5 → (2, 5)
for x = 0 → y = 3(0) - 1/3 = 0 - 1/3 = -1/3 → (0, -1/3)
for x = 2 → y = 3(2) - 1/3 = 6 - 1/3 = 5 2/3 → (2, 5 2/3)
