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2 years ago

Priscilla can make 4 bracelets in 18 minutes. At this rate, how many bracelets can she make in 54 minutes?

Mathematics

1 answer:

Jobisdone [24]2 years ago

6 0

Answer:

13 full bracelets

Step-by-step explanation:

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2 years ago

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The areas of two similar triangles are 75m2 and 300m2. The length of one of the sides of the second triangles is 9m. What is the

Ymorist [56]

Answer:

4.5 m

Step-by-step explanation:

The area of two similar triangles are 75 m2 and 300 m2. This gives you the scale factor of the triangles:

$\dfrac{A_{small}}{A_{large}}=k^2\Rightarrow k^2 =\dfrac{75}{300}=\dfrac{3}{12}=\dfrac{1}{4}\Rightarrow k=\dfrac{1}{2}.$

Then you can find the length of the corresponding side:

$\dfrac{side_{small}}{side_{large}}=k\Rightarrow =\dfrac{side_{small}}{9}=\dfrac{1}{2},\ side_{small}=\dfrac{9}{2}=4.5\ m.$

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3 years ago

Hi can someone please help me?

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3 years ago

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62. Height Kirsten places her surveyor's telescope on the top of

Solnce55 [7]

Answer:

21 feet

Step-by-step explanation:

Given :

Height of the tripod above the ground = 5 ft

Elevation = 8°

Distance of the tree from the tripod = 120 ft

Therefore from the figure, we can find the height of the tress as:

$\tan 8 ^\circ = \frac{BC}{AB}$

$0.1405 = \frac{BC}{120}$

∴ BC ≈ 16

Therefore, CE = BC+BE

= 16 + 5

= 21

Therefore the height of the tree is 21 feet.

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3 years ago

Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

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3 years ago