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Aleks [24]
3 years ago
7

consider a circle with a radius of 10 centimeters. What is the length of the arc that measures 60° for the given circle.

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

3 1/3π

Step-by-step explanation:

First, you have to find the circumference. The circumference, based on the equation of 2rπ, comes out as 20π. Since you have to find the length of the arc that is 60 degrees, divide 60 by 360 to see how much of the circle 60 degrees is. It results in 1/6, so then you simply have to multiply 20π by 1/6.

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Use photomath if you don’t a understand! it will help you alot

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2 years ago
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A taxi driver charges $3 for every kilometre driven, plus $4 per trip.
Stels [109]
Last one is the answer pretty sure
6 0
2 years ago
A circle has a diameter of 16 yd. What is its circumference?
masha68 [24]

Answer:

50.24 yards=Circumference

Step-by-step explanation:

So first the formula to find circumfence is π*diameter

The diamtere is 16

π is told to be counted as 3.14

3.14*16=50.24

So the Circumfrnce is 50.24

3 0
3 years ago
|3y-1|&gt;5<br> Solve the absolute value inequalities by making a compound inequality
Fantom [35]

Hi there!

We can begin by solving the inequality using the positive and negative terms:

3y - 1 > 5

Add 1 to both sides:

3y > 6

Divide both sides by 3:

y > 2

Now, solve the negative:

-(3y - 1) > 5

Distribute the -1:

-3y + 1 > 5

Subtract 1 from both sides:

-3y > 4

Divide both sides by -3. REMEMBER to flip the sign.

y < -4/3

'y' has to be LESS than -4/3 and greater than 2, so:

y < -4/3, y > 2

7 0
2 years ago
Find the equation for the line that passes through -1,-2 and 4,3. Is the point 3,1 on the line
DaniilM [7]

Answer:

  • y = x -1
  • no

Step-by-step explanation:

A graph quickly answers this question.

__

The given points have a horizontal difference of 4-(-1) = 5 and a vertical difference of 3-(-2) = 5, so the slope of the line between them is ...

  m = Δy/Δx = 5/5 = 1

The point-slope form of the equation for a line can be written ...

  y = m(x -h) +k . . . . . for slope m through point (h, k)

Using the first point and the slope we found, we can write the equation as ...

  y = 1(x -(-1)) +(-2)

  y = x -1 . . . . . . . . . simplify; this is the equation of the line

__

When we try the third point in this equation, we get ...

 y = 3 -1 = 2 ≠ 1 . . . . . the third point is not on the line

3 0
3 years ago
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