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V125BC [204]
3 years ago
13

If $2300 is spent on vacations or travel each year, estimate how much should be set aside each month for those expenses?

Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0

The Answer Is A. above me is the example.

Lina20 [59]3 years ago
4 0
12 months in a year
2300/12
we can round 2300 to 2400 (because it is an estimate) and divide by 12 to give an approximation of $200 each month
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Prove the divisibility of the following numbers:
Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}

(B)

72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}

In this case, it is easier to also factor the divisor to primes:

72^{63}=2^{189}\cdot 3^{126}

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}

6 0
3 years ago
Tarzan travels 33 miles per hour. How long does it take him to travel
posledela

Answer:

40 mins

Step-by-step explanation:

33/60 = 0.55

22/0.55 = 40

5 0
4 years ago
Question 1: A ratio of 28 to 12 can be expressed in simplest form as:
vichka [17]
It’s 7:3
Explanation
It’s 7:3 because 28 divided by 4 is 7 and 12 divided by 4 is 3
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3 years ago
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3 years ago
Select the list that correctly includes all of the coefficients from the problem
matrenka [14]

Answer:

( B.) 6, 1, -2 , -4

Step-by-step explanation:

A coefficient is a number multiplied by a variable. So, in this case let's take a look at the problem.

-2+6y+m-2y+8-4m

Now we have to find the numbers that have a variable next to it

which are 6,m,-2, and -4

(If you are wondering that why m is a coefficient its because it is also known as 1m)

Final answer = 6, 1, -2 , -4

Hope this helps!

7 0
3 years ago
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