Carlos got 130 pieces of candy on Halloween and 39 of them were lollipops what percent of the pieces of candy were lollipops

Select the correct answer!<br> Help asap thanks

tester [92]

The area of the shaded region is 3.125π - 6. The correct option is E. 3.125π - 6

<h3>Calculating area </h3>

From the question, we are to determine the area of the shaded region

The area of the shaded region = Area of the semicircle - Area of the triangle

First, we will determine the diameter, d, of the semicircle

d² = 3² + 4² (<em>Pythagorean theorem</em>)

d² = 9 + 16

d² = 25

d = √25

d = 5

∴ Diameter of the semicircle is 5

Thus,

Radius, r = 5/2 = 2.5

Now,

Area of the shaded region = 1/2(π×2.5²) - 1/2(3×4)

Area of the shaded region = 1/2(π×6.25) - 1/2(12)

Area of the shaded region = 3.125π - 6

Hence, the area of the shaded region is 3.125π - 6. The correct option is E. 3.125π - 6

Learn more on Calculating area here: brainly.com/question/14989383

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7 0

2 years ago

1). If the discriminant of a quadratic equation is 28 describe the roots

Ganezh [65]

1)B two real roots.
2)D two complex roots.
3) and 4) later

6 0

4 years ago

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What is m ABC?<br> m ABC = 15°<br> m ABC = 45°<br> mABC = 60°<br> m ABC = 75°

Amiraneli [1.4K]

Answer:

C) 60

Step-by-step explanation:

m ABC is 60 degrees

3 0

3 years ago

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The graph of this function is shifted downwards and the axis of symmetry remains x=1. Which function below the equation of the n

Natali5045456 [20]

Answer:

$y=-x^{2}+2x$

$y=-x^{2}+2x-4$

$y=-x^{2}+2x-3$

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex

The axis of symmetry is equal to the x-coordinate of the vertex

so

$x=h$

If a> 0 then the parabola open upward (vertex is a minimum)

If a< 0 then the parabola open downward (vertex is a maximum)

In this problem we have

$y=-x^{2} +2x+3$

The vertex is the point $(1,4)$ ------> observing the graph

The axis of symmetry is $x=1$

If the graph of this function is shifted downwards and the axis of symmetry remains x=1

then

The x-coordinate of the vertex of the new graph must be equal to 1

The y-coordinate of the vertex of the new graph must be less than 4

The parabola of the new graph open downward

therefore

<u>Verify each case</u>

case a) $y=-x^{2}+2x$

Convert to vertex form

$y=-(x^{2}-2x)$

$y-1=-(x^{2}-2x+1)$

$y-1=-(x-1)^{2}$

$y=-(x-1)^{2}+1$

The vertex is (1,1)

therefore

The function could be the equation of the new graph

case b) $y=-x^{2}-2x+3$

Convert to vertex form

$y-3=-(x^{2}+2x)$

$y-3-1=-(x^{2}+2x+1)$

$y-4=-(x+1)^{2}$

$y=-(x+1)^{2}+4$

The vertex is (-1,4)

therefore

The function cannot be the equation of the new graph

case c) $y=-x^{2}+2x-4$

Convert to vertex form

$y+4=-(x^{2}-2x)$

$y+4-1=-(x^{2}-2x+1)$

$y+3=-(x-1)^{2}$

$y=-(x-1)^{2}-3$

The vertex is (1,-3)

therefore

The function could be the equation of the new graph

case d) $y=-x^{2}+2x+4$

Convert to vertex form

$y-4=-(x^{2}-2x)$

$y-4-1=-(x^{2}-2x+1)$

$y-5=-(x-1)^{2}$

$y=-(x-1)^{2}+5$

The vertex is (1,5)

therefore

The function cannot be the equation of the new graph

case e) $y=-x^{2}+2x-3$

Convert to vertex form

$y+3=-(x^{2}-2x)$

$y+3-1=-(x^{2}-2x+1)$

$y+2=-(x-1)^{2}$

$y=-(x-1)^{2}-2$

The vertex is (1,-2)

therefore

The function could be the equation of the new graph

8 0

3 years ago

Answer me pleaseeee. What is 3*3*3*3*3*3*3*3*8*8*0*8*8*9*8*6? Gk test

olchik [2.2K]

Answer:

0

Step-by-step explanation:

Since we're multiplying by 0, the entire product becomes 0.

6 0

2 years ago

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