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frosja888 [35]
3 years ago
12

Define the method equals for the window class . two windows will be considered equal if they are the same size and at the same p

osition
Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0
Equating "equal" as symmetrical:
 
Two windows of the same size and placed in the same position is considered symmetrical. In an example where one window is placed at a certain distance from a wall and a certain distance from the floor, another window of the same size is also placed in the opposite side of the first window (based on a constant center) with the same distance from the floor and wall. The two windows can be considered equal. 
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The average amount of time it takes Greg to mow x lawns can be defined by the expression 28x + 5. In this scenario, what does th
inna [77]

Answer:

the answer is 140 hope this helped

6 0
3 years ago
Please help and explain please!
larisa86 [58]

Answer: 48

Step-by-step explanation: All you are doing is substituting x and y with the numbers it gives u then u just solve. 2 to the 4th power is 16. 4 to the 3rd power is 64 and then times .5 gives u 32. then u add and get 16+32=48

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3 years ago
Y'all- this question make's 0 sense to my big brain help me out
gregori [183]

Answer:

D. for the first one, A. for the second (not certain)

Step-by-step explanation:

1. 36/2 (two books every visit) = 18, multiplied by 3 because that's how many often he does to the library (every 3 weeks)

2. 13/2 = w/5 because for every 13 cups of water, there is two cups of cleaner, so for w (unknown amount of water) there would be 5 cups of concontrated cleaner.

3 0
4 years ago
6x what equals 72<br> I really need help on my math today
gayaneshka [121]
6 times a number is 72.
Divide 72 by 6 to get the number.
72/6=12

Check:
6 x 12=72

Hope this helps. 
7 0
3 years ago
Read 2 more answers
The owner of a construction company would like to know if his current work teams can build room additions quicker than the time
frez [133]

Answer:

The claim that the current work teams can build room additions quicker than the time allotted for by the contract has strong statistical evidence.

Step-by-step explanation:

We have to test the hypothesis to prove the claim that the work team can build room additions quicker than the time allotted for by the contract.

The null hypothesis is that the real time used is equal to the contract time. The alternative hypothesis is that the real time is less thant the allotted for by the contract.

H_0: \mu=0\\\\H_1: \mu

The significance level, as a storng evidence is needed, is α=0.01.

The estimated standard deviation is:

s_M=\frac{s}{\sqrt{n}}=\frac{0.2}{\sqrt{16}} =0.2/4=0.05

As the standard deviation is estimated, we use the t-statistic with (n-1)=15 degrees of freedom.

For a significance level of 0.01, right-tailed test, the critical value of t is t=2.603.

Then, we calculate the t-value for this sample:

t=\frac{x-\mu}{s_M} =\frac{-0.32-0}{0.05}= -6.4

As the t-statistic lies in the rejection region, the null hypothesis is rejected. The claim that the current work teams can build room additions quicker than the time allotted for by the contract has strong statistical evidence.

8 0
3 years ago
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