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3 years ago

Let y=21 and x=1.5 if y varies directly with x find y when x=9

2 answers:

8 0

Y would be 42. if you multiple 1.5 by 3 it will be 9. so if divide 21 by 1.5 it equals 14 so multiple 14 by 3 it gives you 42

AnnZ [28]3 years ago

7 0

If $y$ varies directly with $x$ then we have the following function:
$y=x + (21 - 1.5)$ or simply $y = x + 19.5$ .
So, when $x=9$ :
$y = 9 + 19.5 = 28.5$

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Check out if I'm right Plz explain..if u have a different answer

Ronch [10]

Answer:

A C

Step-by-step explanation:

A is true.The numerator does have 3 terms. The constant term (the 3 at the end) is still a term and counts as a term.

A constant term does not count as a coefficient so b is not right, just as you have indicated by not underlining it.

C is true. In fact, 2 is the leading coefficent of the denominator.

Either A is true or D is, but I don't think they both are. You need a modifier to claim that D is true. If the statement said the numerator has at least 2 terms then both A and D would be true. Without the at least, you have to pick one and the one I choose is A

This is the tough one. Very sticky. You would think it is true, but it isn't. A constant term is not a coefficient. Coefficients only count when they are with "x"s.

8 0

3 years ago

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Alexxx [7]

Answer:

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Step-by-step explanation:

6 0

3 years ago

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vovikov84 [41]

Answer:

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Step-by-step explanation:

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3 years ago

Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
to get,

$\cos(x) = \sqrt{1 - ( { \frac{3}{5} })^{2}} = \frac{4}{5}$

We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

4 0

3 years ago

Divide and simplify 4/7÷(-11/2)

lys-0071 [83]

Answer: $-\frac{8}{77}$