Question

If tan=4/3 in quardrant 1 find cos and sin

Answer 1

 

$\displaystyle\bf\\If~tan\,\theta=\frac{4}{3}~~then\\\\sin\,\theta=\frac{4}{\sqrt{4^2+3^2}}=\frac{4}{\sqrt{16+9}}=\frac{4}{\sqrt{25}}=\frac{4}{5}\\\\\boxed{\bf~sin\,\theta=\frac{4}{5}}\\\\\\cos\,\theta=\frac{3}{\sqrt{4^2+3^2}}=\frac{3}{\sqrt{16+9}}=\frac{3}{\sqrt{25}}=\frac{3}{5}\\\\\boxed{\bf~cos\,\theta=\frac{3}{5}}$

Answer 2

Answer:

cos = 3/5

sin = 4/5

Step-by-step explanation:

tan=4/3 Q1

if you use Pythagorean theorem

$c {}^{2} = a {}^{2} + b {}^{2} \\ c {}^{2} = 4 {}^{2} + 3 {}^{2} \\ c {}^{2} = 16 + 9 \\ c {}^{2} = 25 \\ c = + - 5$

Becauseof Q1

c=5

to picture

sin = 4/5

cos = 3/5