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inna [77]
3 years ago
7

Standing at a trailhead, you look up at a 54 degree angle and see your friend's cell phone reflecting the sun. You know that she

is at the top of the 1200-foot cliff and you call her to say you'll meet her at the bottom of the cliff. How many feet will you have to walk to meet?

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

The answer is 870 feet.

Step-by-step explanation:

Let's make a diagram (look at the end of the explanation).

We can solve this problem by using trigonometry.

Recall the trigonometric ratios:

sin(\alpha)=\frac{opposite}{hypotenuse}

cos(\alpha)=\frac{adjacent}{hypotenuse}

tan(\alpha)=\frac{opposite}{adjacent}

As we know the size of the opposite cathetus to 54^\circ and we must work out the size of the adjacent cathetus (let's call it <em>x</em>), we can pick the tangent ratio (remember to use the <em>degree </em><em>-deg-</em> mode of the calculator):

tan(54^\circ)=\frac{1200}{x}

1.38=\frac{1200}{x} (to 3 significant figures)

1.38 x = 1200

x = 1200 : 1.38

x = 870

Therefore, you will have to walk 870 feet (to 3 sf) to meet your friend.

Marat540 [252]3 years ago
5 0
So check the picture below

recall your SOH CAH TOA \bf sin(\theta)=\cfrac{opposite}{hypotenuse}&#10;\qquad \qquad &#10;% cosine&#10;cos(\theta)=\cfrac{adjacent}{hypotenuse}&#10;&#10;\\ \quad \\\\&#10;% tangent&#10;tan(\theta)=\cfrac{opposite}{adjacent}

which identity uses only
angle
opposite
adjacent?

well, is Ms Tangent.. thus  \bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(54^o)=\cfrac{1200}{x}

solve for "x", make sure your calculator is in Degree mode, since the angle is in degrees

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Step-by-step explanation:

If we were to flip the solid on the left so its parallel to the solid on the right, we would be able to compare the two more easier.

We can see that the right solid has dimensions of:

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cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

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To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

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