How is the earthworm adapted to its feeding habits

1 answer:

4 0

Hi there,

How is the earthworm adapted to its feeding habits?

Well a earthworms are tube shaped, some worms such as segmented worms can be found in soil.They are there to stay moist and to feed on organic matter.

So an earthworm's digestive tract is laid out straight from the oral orifice to the anus. The parts of the digestive tract regulate or absorb the nutrients from every meal.

Hope this helps!

I used to have a worm farm myself, it was really cool to see really up close on how worms live and how they feed on organic matter in the soil.

You might be interested in

All of the following are environmental influences except ____________. A. Living conditions B. Genes C. Prenatal care D. Media P

larisa [96]

Answer: B. Genes

Explanation:

Got it right on the test.

7 0

3 years ago

This question is for zoology

musickatia [10]

Answer:

Explanation:

All Cnidarians have appendages with stinging cells in their tips which are utilized to capture and stifle prey. In truth, the phylum title "Cnidarian" actually implies "stinging animal." The stinging cells are called cnidocytes and contain a structure called a nematocyst. The nematocyst could be a coiled thread-like stinger.

6 0

2 years ago

What is the best description of chromosomes by the end of metaphase II of meiosis?

Ugo [173]

I believe the answer would be B where the condensed chromosomes line up at the equator of the cell.

6 0

3 years ago

9. In guinea pigs, rough coat is dominant (R) to smooth coat (r) and black coat (B) is dominant to white coat (b). A rough black

lisabon 2012 [21]

Answer:

the genotype of the parent guinea pigs are as follows:

RrBb (rough, black) and Rrbb (rough, white)

Explanation:

Since the phenotype of smooth coat is present in the offspring, the parent genotype cannot have RR alleles for their coat. Similarly, the rough, black parent cannot have BB alleles in its genotype because that will not yield a white coat color in its offspring.

After making the dihybdrid cross, the probability obtained for each phenotype is given below:

rough black: $\frac{3}{8}$