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3 years ago

4 thousands 7 hundreds = 47

Mathematics

1 answer:

motikmotik3 years ago

4 0

If there is 4 thousands and 7 hundreds is 4,700

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A person places $103 in an investment account earning an annual rate of 1.9%, compounded continuously. Using the formula V = P e

Advocard [28]

Answer:

$115.36

Step-by-step explanation:

Given data

P=$103

r=1.9%

t= 6 years

The expression for the amount is given as

$V = P e ^{r t}$

substitute

$V = 103*e^{0.019 *6}$

$V = 103*e^{0.114}\\\\V = 103*1.120\\\\V = 115.36\\\\$

Hence the final amount is $115.36

7 0

3 years ago

What is the name the special hat worn during Mardi Gras?

PilotLPTM [1.2K]

Hello!!

I believe the correct answer to your question is capuchon. These are cone shaped ceremonial hats worn durning Mardi Gras.

Hope I helped with a detailed description. Have a nice night!
~Brooke❤️

3 0

3 years ago

A random survey of the quality of city parks is taken. Sixty-five percent of the people surveyed were pleased with the condition

Georgia [21]

Answer:

DWWDDWDWDAWDWDAWD

Step-by-step explanation:

WDWDAWDDAWD AWDDAWD

3 0

3 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

X^2-15x-108 Factoring need help

sveticcg [70]

x=15-657/2=15-373/2=-5.316

x=15+657/2=15+373=20.316

3 0

3 years ago