Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
Answer:
4 / 9 probability of getting a red
Step-by-step explanation:
How many marbles are there total?
4 red + 2 yellow + 3 green = 9 marbles total
P( red marble) = 4 red / 9 total = 4/9
Answer:
60 yards back
Step-by-step explanation:Mutiply 4 and 15
Answer:
Width = 18, height = 3
Or
Width = 6, height = 9
Step-by-step explanation:
Complete question
( A piece of sheet metal 24 inches wide is bent to form a gutter as shown in the picture below, if the cross sectional area is 54 square inches, find the depth of the gutter).
X = width, Y = height
X - 2y = 24........ equation i
X = 24 - 2y.......... equation ii
Area = xy
54 = xy........ equation iii
Put equation ii into equation iii
54 = (24 - 2y) * y
54 = 24y - 2y²
2y² - 24y + 54 = 0........ equation iv
Solving equation iv using quadratic methods,
Factors = (y-3), (y-9)
(Y-3)(y-9) = 0
y = 3 or y = 9
Substitute y = 3 or y = 9 into equation ii
X = 24 -2(3) = 18 or x = 24 - 2(9) = 6
If Width = 18, height = 3
Or
Width = 6, height = 9
Answer:
It's C.
Step-by-step explanation: