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zubka84 [21]
3 years ago
15

Please help and explain the answer as best as you can so i can understand it better! (6th grader)​

Mathematics
1 answer:
qwelly [4]3 years ago
3 0

Answer:

The rug will fit. The rug is smaller than the parallelogram.

Step-by-step explanation:

This question is testing to see if you can figure out how the rug may fit in the room.

The rug does fit. Here's how we know.

The only given information from the question is...

  1. Length and Width of the <em>Rectangular Rug</em>
  2. Area of the Parallelogram

Notice that you can use the Length and the Width to get the area of the Rectangular Rug. We need to find the area of the rectangle so we can compare it to the parallelogram.

The area of the Parallelogram is listed at : 108 sqft

The area of the rectangular rug is : 60 sqft

  • <em>Area of rectangle = Length * Width</em>
  • <em>6 * 10 = 60</em>

<em />

The question now asks us if the rug will fit in her room. Well, 60 sqft is less than 108 sqft. So, yes, it will fit.

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lozanna [386]
Standard equation of a circle: <em>(x-h)² + (y-k)² = r²</em> where <em>(h, k)</em> is the center and <em>r </em>is the radius. In the case of our equation here, <em>(x-5)² + (y+3)² = 25</em>, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

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Distance = \sqrt{(-6)^2+3^2}

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8 0
3 years ago
What is 1.7¯ expressed as a fraction in simplest form? <br> 13/7<br> 25/9<br> 8/7<br> 16/9
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7 0
3 years ago
Read 2 more answers
When x=1/2, what is the value of 8x-3 over x?
IgorLugansk [536]

Answer:

2

Step-by-step explanation:

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Your answer is 2, hope this helps

5 0
2 years ago
Read 2 more answers
Can you help me to get this question please
zzz [600]

Part A).
If 100 fish all had the same weight, and they weighed
235 pounds when they were all on the scale at the
same time, then each fish weighed

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Part-B). 
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                 235 / 100  =  2.35 pounds .

Part-C).
If there were only 10 fish but their total weight was still 235 pounds,
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Now, each fish would have to weigh   235 / 10 pounds .

That number is        235/10  =  23.5 pounds.

If there were only 1/10 as many fish, then in order to add up to the
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