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Anarel [89]
3 years ago
5

Harita must memorize 90 measures of music for her cello solo at a concert. She plans on memorizing 18 new measures for every 3 d

ays of practice. Which equation can be used to determine m, the number of measures Harita still needs to memorize, as a function of d, the number of days of practice since she began learning the piece?
Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Harita still needs to memorize, as a function of d, the number of days of practice since she began learning the piece <span>m = 90 - 6d</span>

vesna_86 [32]3 years ago
7 0

Answer:

m=90-6 days or b

Step-by-step explanation:

i got a hundred on the quiz...

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When driving in England, Brian drove through several speed cameras. On one drive, Brian left his hotel and after 7 minutes he wa
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Solution :

The formula for the linearization of a function $f(x)$ at a point $x$ = a is given as

$L(x)=f(a)+(x-a)f'(a)$

Assuming the time is t and the distance travelled is $f(t)$, that makes the speed as $f'(t)$.

So substituting them in the linearization formula,

A. At t = 7 minutes

   f(7) = 2.5 km

    f'(7) = 0.5 kpm

  ∴ $L_7(t)=f(7)+(t-7)f'(7)$

             $=2.5+(t-7)0.5$

              $=2.5+0.5t-3.5$

              $=0.5t-1$

B. At t = 18 minutes

      f(18) = 14.8 km

    f'(18) = 0.8 kpm

  ∴ $L_{18}(t)=f(18)+(t-18)f'(18)$

               $=14.8+(t-18)0.8$

              $=14.8+0.8t-14.4$

              $=0.8t-0.4$

C. Substituting the value of t as 14 in both the linearization to determine the position at 14 minutes, we get

$L_7(14)=0.5(14)-1.0$

          = 7 - 1

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$L_{18}(14)=0.8(14)+0.4$

            = 11.2 + 0.4

            = 11.6 km

D. According to the linearization at 7, the distance travelled between the 7 minutes and 14 minutes is = 6 km - 2.5 km

                                           = 3.5 km

And between the 14 minutes and 18 minutes is = 14.8 km - 6 km

                                                                              = 8.8 km

This is an average speed of 0.5 kpm in the first interval and an average speed of 2.2 kpm.

Now, according to the linearization of 18, the distance travelled between the 7 minutes and the 14 minutes is = 11.6 km - 2.5 km

                                                           = 9.1 km

And between 14 minutes and 18 minutes is = 14.8 km - 11.6 km

                                                                       = 3.2 km

This gives an average speed of 1.3 kpm in the first interval and 0.8 kpm in the second interval.

Therefore, the second approximation is the better one since the average speed are closer to the actual readings in the second linearization.  

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