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liraira [26]
4 years ago
10

Decide which variable to isolate. Then substitute for this variable, and solve the system. y = x - 5, x + y = 9

Mathematics
1 answer:
jolli1 [7]4 years ago
4 0

Answer:

x = 7

y = 2

Step-by-step explanation:

x + y = 9 but y = x - 5

x + (x - 5) = 9

2x - 5 + 5 = 9 + 5

2x/2 = 14/2

x = 7

y = x - 5

y = (7) - 5

y = 2

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Rectangle RSTU and the image R’S’T’U’ are graphed on the coordinate grid below.
Ksju [112]

The rectangle  R’S’T’U’ is a 90° counterclockwise rotation of RSTU so options (A) and (C) will be correct.

<h3>What is a rectangle?</h3>

The rectangle is a geometrical figure in which opposite sides are equal.

The angle between any two consecutive sides will be 90 degrees.

Area of rectangle = length × width.

Perimeter of rectangle = 2( length + width).

Given the rectangle RSTU if we plot it then it becomes a major horizontal rectangle.

If we transpose into R’S’T’U’ then it rotates 90 degrees counterclockwise and becomes a major vertical ractangle.

Hence the rectangle RSTU will rotate 90° counterclockwise to form  R’S’T’U’.

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2 years ago
True or false. There are some parallelograms that are rectangles.
RideAnS [48]

True, because a parallelogram is a four-sided rectangular figure with opposite sides parallel.  This is a way to describe a rectangle as well.  The only difference is that rectangles must have 90 degree angles, but it is possible for a parallelogram to have 90 degree angles as well.  This also means that all rectangles are technically parallelograms as well.

6 0
4 years ago
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3 decagrams = centgrams
notsponge [240]

Answer:

3,000

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3 years ago
The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length
andrew11 [14]

we know that

In a right triangle

Applying the Pythagorean Theorem

c^{2} =a^{2} +b^{2}

where

a and b are the legs of the triangle

c is the hypotenuse of the triangle

Step N 1

<u>Assume that the third side is a leg</u>

In this case we have

a=12\ in\\c=15\ in\\ b=?

c^{2} =a^{2} +b^{2}

Solve for b

b^{2}=c^{2} -a^{2}

substitute the values

b^{2}=15^{2}-12^{2}

b^{2}=81

b=9\ in

Step N 2

<u>Assume that the third side is the hypotenuse</u>

In this case we have

a=12\ in\\b=15\ in\\ c=?

c^{2} =a^{2} +b^{2}

substitute the values

c^{2}=12^{2}+15^{2}

c^{2}=369

c=19.2\ in

Step N 3

<u>Find the difference of the third sides</u>

19.2\ in-9\ in=10.2\ in

therefore

<u>the answer is</u>

10.2\ in

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Can you help me with these too?<br> its for a geometry final practice<br> plisss
ANTONII [103]

Answer:

The answer is B

Step-by-step explanation:

6 0
3 years ago
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