Answer:
It Is true and then false
Step-by-step explanation:
The correct answer is A. y = 2x +1
Explanation:
An equation is a statement that shows equality. In this context, the equation should lead to two equal numbers even if the values of y and x change. In this context, the correct equation is y= 2X + 1 because this is the only one, in which, the value of Y is always equivalent to 2x + 1. To prove this, let's replace y and x for the values of the table.
First column
5 = 2 · 2 + 1
5 = 4 + 1
5 = 5
Second Column
9 = 2 · 4 + 1
9 = 8 + 1
9 = 9
Third column
13 = 6 · 2 + 1
13 = 12 + 1
13 = 13
Fourth column
17 = 8 · 2 + 1
17 = 16 + 1
17 = 17
The percent of runners between these two times is 47.72.
We find the z-scores associated with each end of this interval using the formula
z=(X-μ)/σ
For the lower end,
z=(4.11-4.41)/0.15 = -0.3/0.15 = -2
Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.0228.
For the upper end:
z=(4.41-4.41)/0.15 = 0/0.15 = 0
Using a z-table we see that the area to the left of, less than, this score is 0.5000.
We want the area between these times, so we subtract:
0.5000-0.0228 = 0.4772
This corresponds with 47.72%.
<h2>Hey there!</h2>
<h3>Here's your required mode </h3>
<h3>Refer to the image above </h3>
<h3>And btw,in the earlier question I've done for mean also you can check that again which I've answered earlier. </h3>
<h2>Hope it helps</h2>
<u>1) </u> 
2) Rectangular shape is square shape patio !
<u>Step-by-step explanation:</u>
Here we have , the area of Bianca’s rectangular backyard patio is represented by the expression x2 – 18x + 81, and the length of the patio is represented by the expression x − 9: We need to find
1. what is the expression for the width of the patio? Explain and show all work.
We know that area of rectangle = 
⇒ 
Factorizing RHS:
⇒ 
⇒ 
⇒ 
⇒ 
2. what special rectangular shape is the patio?
Now , we see that

A rectangle whose length & width are equal is known as a square ! Hence , Rectangular shape is square shape patio !