Answer:
Step-by-step explanation:
You didn't mark your graph but I'm assuming the point is (1,2)
You notice how the function stops at the point? x and y can not be above that point because there is no line above it.
The domain of the function means what can x possibly be.
The maximum value of x in this function is 1 because that's the x value of the point where the function ended. This means x can at most be one or x≤1. So the domain is x≤1.
The range of the function means what can y possibly be.
The maximum value of y in this function is 2 because that's the y value of the point where the function ended. This means y can at most be two or y≤2. So the range is y≤2.
Answer:
no
Step-by-step explanation:
Answer:
320 hope it helps :)
Step-by-step explanation:
The answer would be 5/2q+9r+6r-20s
Explanation
We have the equation
5(1/2q+3r-4s)
which would equal
5/2q+15r-20s
so with the information
We can subtract 6r from 15r to get 9r
15r-6r=9r
+9r would be the missing piece
So we substitute it in to make the equation true.
5/2q(+9r)+6r-20s
Hope this helps or was correct