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2 years ago

Write an equation for the line that is parallel to the given line and passes through the given point Y= 1/2 x -8 (-6 ,-17)

1 answer:

8 0

Parallel to : y = 1/2x - 8

Passes through (-6, -17)

Our given slope is 1/2.

Plug the given coordinates into point-slope form.

y - y₁ = m(x - x₁)

y - (-17) = 1/2(x - (-6))

Simplify.

y + 17 = 1/2(x + 6) ← Your answer.

However, sometimes teachers want this simplified even further.

So, simplify this.

y + 17 = 1/2x + 3

Subtract 17 from both sides.

y = 1/2x + 3 - 17

Simplify.

y = 1/2x - 14 ← Slope-intercept form.

Standard form → -1/2x + y = -14

~Hope this helped!~

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Which is the more precise measurement? *

RSB [31]

Answer:

19.775

Step-by-step explanation:

I assume your asking which number goes the most in depth to find that look for the number that has the most decimal places

6 0

2 years ago

Easy Area problem <br><br> Need it fast

Gekata [30.6K]

Answer:

just subtract the area of the rectangle from the area of the carpet

fine I'll do it

Area of a rectangle= lb

Area of a square= a^2

Area of the remaining area= lb - a^2

= (12*4) - (2*2)

= 48-4

= 44 ft^2

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2 years ago

Kyla used 550 grams of wool to knit a sweater, a hat, and a scarf. For the hat she used 5 times less wool than the sweater and 5

Brrunno [24]

This is the concept of algebra, to calculate the proportion of wool in each item we proceed as follows;
Let the amount of wool used for hat be x
amount of wool in sweater will be 5x
the amount of wool used in scarf will be x-5
therefore the total amount of wool will be:
x+5x+(x-5)=550
x+5x+x-5=550
7x-5=550
7x=550+5
7x=555
hence;
x=555/7
x=79
the amount used in hat x=79g
amount used in sweater 5x=395g
amount used in scarf=79-5=74g

5 0

3 years ago

If wandas motherly take-home is $3,000 her fixed monthly expenses are $2,575 and get average monthly variable expenses are $855

anastassius [24]

Send a picture of the assignment thank u #1

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1 year ago

Simplify

OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

$\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}$

we need to simplify that

$x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)$

so we can continue

$\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}$

and we can put all together

$\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}$

3 0

2 years ago