BD = AC/2
4x+2 = (5x+13)/2
2(4x+2) = 5x+13
8x + 4 = 5x+13
8x - 5x = 13 -4
3x = 9
x = 3
<h3>Sample space = {a,b,c,d,e,f}</h3><h3>Event space = {a,c}</h3>
We simply list all of the letters mentioned as they are the possible outcomes. We can only pick one item from the sample space. The event space is the set of outcomes where we want to happen (picking either an 'a' or 'c').
Answer:
4/675
Step-by-step explanation:
There can be 90 two-digit numbers ranging from 10 to 99. There will be
90 x 90= 8100 possibilities of randomly selecting and combining 2 entire two-digit numbers, if we find ax b to be distinct from bx a. When 10 is first chosen, there may be 9 two-digit numbers that could be combined within the required range for a product When 11 is chosen first, then the second two-digit number has 9 possibilities. 12 has seven options; 13 has six options; 14 has five options; 15 has four options; 16 has three options; 17 has two options; 18 has 2 options; and 19 has one option. It provides us 48 total choices so the likelihood that the combination of two randomly chosen two-digit whole numbers is one of theses these possibilities is thus 48/8100 = 4/675.
The reduced fraction that represents the sales attained is 17/20
<h3>How to determine the fraction?</h3>
The given parameters are:
Expected = $6000
Attained = $5100
The fraction is represented as:
Fraction = Attained/Expected
So, we have:
Fraction = 5100/6000
Divide by 300
Fraction = 17/20
Hence, the reduced fraction is 17/20
Read more about fractions at:
brainly.com/question/1622425
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