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Inessa05 [86]
3 years ago
8

I need help with my khan, plz help meeee (7th-grade math)

Mathematics
1 answer:
adoni [48]3 years ago
6 0

Answer:

The equation is ⇒ 7( x - 0.75 ) = 2.8

The normal price of one cookie = $1.15

Step-by-step explanation:

Let the normal price is x

So, the cost of cookie today is x - 0.75

The price of 7 of them will be $2.8

So the equation will be:

<u> 7( x - 0.75 ) = 2.8</u>

Solve for x:

x - 0.75 = 2.8/7 = 0.4

x = 0.4 + 0.75 = 1.15

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tamaranim1 [39]
84(600 x 0.07)
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3 0
3 years ago
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Find the value of t, rounded to the nearest tenth
sergij07 [2.7K]

<u>Given</u>:

Given that RST is a right triangle.

The measure of ∠R is 35°.

The length of ST is 12 units.

The length of the hypotenuse is t units.

We need to determine the value of t.

<u>Value of t:</u>

The value of t can be determined using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

where \theta=R, the side opposite to ∠R is ST and hypotenuse is SR.

Substituting these values, we get;

sin \ R=\frac{ST}{SR}

Substituting ST = 12 and SR = t, we get;

sin \ 35^{\circ}=\frac{12}{t}

Simplifying, we get;

t=\frac{12}{sin \ 35^{\circ}}

t=\frac{12}{0.574}

t=20.9

Thus, the value of t is 20.9 units.

5 0
3 years ago
Art and his friends spent $62 at the movies. Admission tickets cost $12 apiece, and a bucket of popcorn costs $7. Which equation
Darya [45]

Answer: 12t+7p=62

Step-by-step explanation:

8 0
3 years ago
Select the correct answer.
fomenos

Answer:

a.2

Step-by-step explanation:

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4 0
4 years ago
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Let the universal set, s, have 66 elements. a and b are subsets of s. set a contains 19 elements and set b contains 34 elements.
Otrada [13]

The cardinality of the union between two sets is given by

N(A\cup B) = N(A) + N(B) - N(A \cap B)

In fact, if an element is in both A and B, it is counted in both N(A) and N(B), so we're counting it twice. By subtracting the cardinality of the interserction, we're taking back one of these "extra-counted" element, and the count is correct. In your case, the numbers are

N(A \cup B) = 19+34-10 = 43

This means that the two sets cover, without repetitions, 43 of the 66 elements in the sets. So, there are

66-43 = 23

elements which are in neither A nor B

5 0
3 years ago
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