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PIT_PIT [208]
3 years ago
12

What is the volume of this rectangular prism? 10/3 4/5 1/5

Mathematics
2 answers:
Oxana [17]3 years ago
8 0

Answer:

I think it will be the answer 10/3

I hope it help you

Lunna [17]3 years ago
7 0

Answer:

.53

Step-by-step explanation:

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Pitágoras filósofo matemático griego biblio entre los años 500 8496 antes de Cristo A qué edad murió y cuántos años hace que mur
Maurinko [17]

Answer:

if you can transfer to englis i may be able to help

Step-by-step explanation:

5 0
3 years ago
There is a quadrilateral MNPQ in which side MN is congruent to side PQ and side NP is parallel to side MQ. The diagonal MP and t
8_murik_8 [283]

Answer: QN = 12

Step-by-step explanation: This quadrilateral is a paralelogram because its 2 opposite sides (NP and MQ) are parallel and the other 2 (MN and PQ) are congruent.

In paralelogram, diagonals bisect each other, which means QR = RN.

If QR = RN:

QR = 6

Then,

QN = QR + RN

QN = 6 + 6

QN = 12

<u>The diagonal QN of quadrilateral MNPQ is </u><u>QN = 12</u><u>.</u>

5 0
3 years ago
The graph below shows a system of equations:
Nostrana [21]
3y = -2x + 2
y = x + 4 (Substitute the y)

3(x + 4) = -2x + 2 (Distribute)
3x + 12 = -2x + 2 (Add 3 to both sides)
+3x       +3x
------------------------------------------
12 = 1x + 2 (Subtract 2 from both sides)
-2         - 2
------------------------
10 = 1x (Divide by 1 on both sides)
10/1 = 1x/1
x = 10 
This is your x-coordinate
4 0
3 years ago
Read 2 more answers
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
Round 3.46 to the nearest integer
mestny [16]

Answer: 3.5 integers can be in decimals too. and any number counts as an integer except for 0

3 0
3 years ago
Read 2 more answers
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